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Eva8 [605]
3 years ago
5

To ensure an excellent bond when brazing, the clearance gap between pipe and fitting must be _______ inches.

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Step-by-step Answer:

Gap must be a maximum of 0.005 inches, and uniform all around.  Round out with a sizing tool if necessary.

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Find Product<br> -3x(8x^2+2x-4)
serious [3.7K]

Answer:

−243−62+12

Step-by-step explanation:

5 0
3 years ago
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What is the slope of the line that contains these points?
Novosadov [1.4K]

Answer:

-2/5

Step-by-step explanation:

We can find the slope of a line by using

m = (y2-y1)/ (x2-x1)

   = (6-4)/(41-46)

    = 2/-5

   = -2/5

8 0
3 years ago
Read 2 more answers
Calculate 3217. km + 13.1 km + 1.30 km. round off if necessary to apply the rule of significant figures for addition and subtrac
QveST [7]
3217 + 13.1 + 1.3 can also be written as

3217.0
+ 13.1
     1.3
----------
<span>3231.4
</span>
Your final answer should be <span>3231.4 or option 4. Hope this helps!</span>
6 0
3 years ago
Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.
Ilya [14]

Answer:

none of them

Step-by-step explanation:

Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.

line 1:  

y – 1 = (x+2)

y = x + 3

slope of line 1 = 1

line 2:  

y + 2 = –3(x – 4)

y + 2 = -3*x + 12

y =  -3*x + 10

slope of line 2 = -3

m1*m2 = 1*(-3 ) = -3

They are not perpendicular

line 3:  

y − 5 = 3(x + 11)

y − 5 = 3*x + 33

y = 3*x + 38

slope of line 3 = 3

m1*m3 = 1*3 = 3

They are not perpendicular

line 4:  

y = -3x –  

slope of line 4 = -3

m1*m4 = 1*(-3 ) = -3

They are not perpendicular

line 5:  

y = x – 2

slope of line 5 = 1

m1*m5 = 1*1 = 1

They are not perpendicular

line 6:  

3x + y = 7

y = -3x + 7

slope of line 6 = -3

m1*m6 = 1*(-3 ) = -3

They are not perpendicular

5 0
3 years ago
Read 2 more answers
Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct
Nana76 [90]

Answer:

Fx=\frac{5\pm\sqrt{25+24} }{6}

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

ax^2+bx+c

Where:

a\neq 0

The roots of this equation can be found using the quadratic formula, which is given by:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

So:

y(x)=3x^2-5x-2=0

As you can see, in this case:

a=3\\b=-5\\c=-2

Using the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}

Therefore, the answer is:

Fx=\frac{5\pm\sqrt{25+24} }{6}

4 0
3 years ago
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