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timofeeve [1]
4 years ago
9

Find the area of the composite figure and round the nearest tenth

Mathematics
2 answers:
kifflom [539]4 years ago
6 0

<u>Answer:</u>

1080 ft^2

<u>Step-by-step explanation:</u>

We are given a composite figure that consists of a triangle and a trapezoid.

We know that the area of these two shapes is given by the following formulas so we will put in the given values to get:

Area of triangle = \frac{1}{2} \times b \times h = \frac{1}{2} \times 16 \times 30 = 240 ft^2

Area of trapezoid = \frac{a+b}{2} h = \frac{16+40}{2} 30 = 840 ft^2

Area of composite figure = 240+840 = 1080 ft^2

Monica [59]4 years ago
5 0

Answer:

The area of the composite figure is 1360 ft.

Step-by-step explanation:

First, you should split up the composite figure into separate shapes.

So to find area of the triangle all the way on the left, you multiply base x height then divide by 2.

<u>30 x 34 = 1020 ÷ 2 = 520.</u>

Then, moving on to next shape, we can break up the trapezoid into a rectangle and a triangle.

To find area of the rectangle you multiply length x width.

<u>16 x 30 = 480.</u>

Finally, we have the last triangle right above the rectangle. Keep in mind that the rectangle does not have a length of 40!

You have to subtract 40 - 16 which equals 24.

<u>30 x 24 = 720 ÷ 2 = 360.</u>

Now that we have all 3 numbers, we simply add them all together and you will get an answer of 1360 ft.

Remember to label your answer!

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Find the area of this regular polygon.<br> Round to the nearest tenth.<br> 8.65 mm<br> [? ]mm2
nadezda [96]

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Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:

a=√{b²+c²−2bc×cos40°}

a=√{149.645−149.645cos40°}

Area Nonagon = (9/4)a²cos40°

=9/4[149.645−149.645cos40°]cot20°

=336.70125[1−cos(40°)]cot(20°)

Applying an identity for the cos(40°) does not get us very far…

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3 years ago
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