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Vlad [161]
3 years ago
11

What is the radius of a circle that has a circumference of 81.64 meters? r =___________a0m

Mathematics
2 answers:
slamgirl [31]3 years ago
5 0
 <span>Radius—r: 
2r(3.14) = 81.64 
6.28r = 81.64 
r = 13 

Answer: 13 cm is the radius.</span>
const2013 [10]3 years ago
3 0
<span>12.99m
</span>make me the brainiest answer
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Solve this for me please ? I do not know the steps or answer
yan [13]
(x-80) = 2*40
x-80 = 80
x=160 degrees
3 0
4 years ago
Can someone help with this ASAP
LenKa [72]

Answer:

x=7cm.

Step-by-step explanation:

A=1/2(a+b)h.

63=1/2(6+12)x.

63=1/2(18)x.

63=9×x.

63/9=9×x/9.

7cm=x.

x=7cm.

3 0
3 years ago
The polynomial p(x)=x^3-7x-6 has a non-factor of (x+1) rewrite p(x) as a product of linear factors.
In-s [12.5K]

Answer:

Using synthetic division suffices to answer your question:

Step-by-step explanation:

Synthetic division is the process by one reduces a large polynomial in your case x^3-7x-6 by a binomial in your case (x+1).

To do so one does the following:

\begin{array}{cccccc}-1|& 1&0&-7&-6\\ & &-1&1&6 \\& 1&-1&-6&0  \end{array}

Since we divided by a linear binomial it reduces the power by one which produces the following quadratic:

(x^2-x-6)

Which can be factored in the following, and I will provide the complete factorization as well:

p(x)=(x+1)(x-3)(x+2)

7 0
3 years ago
Find the quotient.<br> 121.5 ÷ 9
maw [93]

Answer:

13.5

Step-by-step explanation:

Entered in Calculator.

4 0
4 years ago
Read 2 more answers
if i have a known points of polynomial(2,5),(3,2) and (4,5). what would be the polynomial function will be?
faltersainse [42]
I think you mean "if the points <span>(2,5), (3,2) and (4,5) satisfy an unknown 3rd degree polynomial, what is the polynomial?"

Since 3 roots {2, 3, 4} are known, we might begin by assuming that this poly would have the form y = ax^3 + bx^2 +  cx + d (which has three factors).  Unfortunately, three roots are not enough to determine all four constants {a, b, c, d}.

So, let's assume, instead, that the poly would have the form y = ax^2 + bx + c.  Three given points should make it possible to determine {a, b, c}.

(2,5):  5 = a(2)^2 + b(2) + c => 5 = 4a + 2b + c

(3,2):  2 = a(3)^2 + b(3) + c   => 2 = 9a + 3b + 5 - 4a - 2b

(4,5):  5 = a(4)^2 + b(4) + c   => 5 = 16a + 4b + 5 - 4a - 2b

Now we have two equations in a and b alone, which enables us to solve for a and b:

</span>2 = 9a + 3b + 5 - 4a - 2b becomes -3 = 5a + b
<span>and 
</span>5 = 16a + 4b + 5 - 4a - 2b becomes 0 = 12a + 2b, or 0 = 6a + b, or 0=-6a-b
<span>
Adding this result to -3 = 5a + b, we get -3 = -a, so a =3.
Thus, since -3 = 5a + b, -3 = 5(3) + b, so b = -18

All we have to do now is to find c.  Let's do this using </span>5 = 4a + 2b + c.
We know that a = 3 and b = -18, so  this becomes   5 = 4(3) + 2(-18) + c.

Thus, 5 = 12 - 36 + c, or c = 29.

With a, b and c now known, we can write the poly as y = 3x^2 - 18x + 29.

Now the only thing to do remaining is to verify that each of the three given points satsifies        y = 3x^2 - 18x + 29.  Try this, please.



5 0
4 years ago
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