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3 years ago

Find the solution set for this equation.

Mathematics

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

m = -5, 0

Step-by-step explanation:

Easiest and quickest way to do this is to graph the equation and find where it intersects the x-axis. If not, then use completing the square or quadratic formula to find your roots.

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denis-greek [22]

Answer:

The ratio of the slant heights of the two cones will also be n : m.

Step-by-step explanation:

See the attached diagram.

If we take the vertical sections along any diameter of the base circle of the cones A and B then the triangular sections as we get will be similar.

Now, ratio of the base of the triangles A and B i.e. the ratio of the diameters of the cones A and B will be 2n : 2m = n : m and this will be the same as the ratios of other two sides of the triangles A and B.

Therefore, the ratio of the slant heights of the two cones will also be n : m. (Answer)

8 0

3 years ago

Jeff goes to the fair and spends a fourth of his money on the ticket and half of his money on food. If he spent a total of $24,

kherson [118]

He arrived with 32 dollars. This is because 1/4 of 32 is 8 and 1/2 of 32 is 16. 16+8=24

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3 years ago

How does the rule for multiplying radicals relate to the symmetry property?

ludmilkaskok [199]

Multiplying radicals is the same procedure as multiplying whole numbers, when you multiply, you get a result, and that result always equal to itself, which is what we know as "Symmetry Property".

Hope this helps!

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3 years ago

Your friends asks you to bring a couple of bags of chips to his party. There are several brands of chips, each a different size

Wewaii [24]

Answer:

i will buy wo different with good price

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Identify the theorem or postulate that is related to the measures of the angles in the pair, and find the unknown angle measures

aleksley [76]

Angles formed when two parallel are intersected by a common transversal include, corresponding, alternate interior and exterior, same-side interior, and vertically opposite angles

The correct option is Same–Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

The reason the selection is correct is as follows:

The given angles are;

m∠1 = (30·x - 30)°. m∠5 = (40·x + 70)°

∠1, and ∠5, are located on the same side of the transversal and are both formed on the interior side of the parallel lines

Therefore, they are same–side interior angles

Same side interior angles theorem states that same side interior angles formed between parallel lines are supplementary

Therefore, we have;

m∠1 + m∠5 = 180°

Which gives;

(30·x - 30)° + (40·x + 70)° = 180°

(70·x + 40)° = 180°

70·x = 180° - 40° = 140°

$x = \dfrac{140^{\circ}}{70} = 2^{\circ}$

m∠1 = (30·x - 30)° = (30 × 2 - 30)° = 30°

m∠1 = 30°

m∠5 = (40·x + 70)° = (40 × 2 + 70)° = 150°

m∠5 = 150°

The correct option is therefore;

Same-Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

Learn more about parallel lines cut by a transversal here:

brainly.com/question/533025

8 0

2 years ago