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3 years ago

WILL GIVE BRIANLIEST TO SOMEONE WHO GIVES ALL ANSWERS!!

Biology

1 answer:

Vaselesa [24]3 years ago

6 0

They didn’t give you a word bank? It’s fine if they didn’t ill answer it either ways I’m just asking first

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When two lineages split from a common ancestor, each accumulates different mutations over long periods of time. The number of mu

Len [333]

Answer:

# of mutations in the exons

Explanation:

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3 years ago

What’s a geographic variation in fossil record?

Debora [2.8K]

Geographical variation refers to differences among populations in genetically based traits across the natural geographic range of a species. ... In the simplest case, we divide these factors into purely genetic versus environmental components to tease apart their relative contributions to observed phenotypic variation.

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3 years ago

What structure on plants is the location where photosynthesis takes place?

Nikitich [7]

Answer:

It's the leaf, or it is called chloroplasts.

Explanation:

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3 years ago

Read 2 more answers

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). Only homozygous individu

White raven [17]

The answer is A. 72.25 percent.

The Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles, and p², q² and 2pq are the frequencies of the genotypes.

The r allele (q) is found in 15% of the population:
q = 15% = 15/100
Thus, q = 0.15

To calculate the R allele frequency (p), the formula p + q = 1 is used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, p = 0.85

Knowing the frequency of the R allele (p), it is easy to determine the frequency of the RR genotype (p²):
p² = 0.85² = 0.7225

Expressed in percentage, p² = 72.25%.

4 0

3 years ago

In cats, curled ears result from an allele, Cu, that is dominant over an allele cu, for normal ears. Black color results from an

just olya [345]

Answer:

Explanation:

Cross : ggCuCu X GGcucu --------Parents

F1 progeny : GgCucu

Two of the F1 cats mate :

Cross : GgCucu X GgCucu

Gametes :

Gg X Gg = GG, Gg, Gg, gg

Cucu X Cucu = CuCu, Cucu, Cucu, cucu

1/4 GG X 1/4 CuCu = 1/16 GGCuCu (black - curled ears)

1/4 GG X 2/4 Cucu = 2/16 GGCucu (black - curled ears)

1/4 GG X 1/4 cucu = 1/16 GGcucu (black - normal ears)

2/4 Gg X 1/4 CuCu = 2/16 GgCuCu (black - curled ears)

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 1/4 cucu = 2/16 Ggcucu (black - normal ears)

1/4 gg X 1/4 CuCu = 1/16 ggCuCu (gray - curled ears)

1/4 gg X 2/4 Cucu = 2/16 ggCucu (gray - curled ears)

1/4 gg X 1/4 cucu = 1/16 ggcucu (gray - normal ears)

Answer : (i). 9/16 black cats, curled ears; 3/16 black cats, normal ears; 3/16 gray cats, curled ears; and 1/16 gray cats, normal ears.

An F1 cat mates with a stray cat that is gray and possesses normal ears :

Cross : GgCucu X ggcucu

Gametes :

Gg X gg = Gg, Gg, gg, gg

Cucu X cucu = Cucu, Cucu, cucu, cucu

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 2/4 cucu = 4/16 Ggcucu (black - normal ears)

2/4 gg X 2/4 Cucu = 4/16 ggCucu (gray - curled ears)

2/4 gg X 2/4 cucu = 4/16 ggcucu (gray - normal ears)

Answer : (i). 1/4 black cats, curled ears; 1/4 black cats, normal ears; 1/4 gray cats, curled ears; 1/4 gray cats, normal ears.

6 0

4 years ago