Answer: Reflect Y-Axis & 10 Units Down
Step-by-step explanation:
I’m not sure if this is correct but
you have used 3/8 of the plants so you will have 5/8 left to use
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Lines are neither perpendicular nor parallel.
Step-by-step explanation:
Step 1:
In equation 1, Y = 5X + 7
In equation 2, Y = -2X -5
Step 2:
Slope Intercept form Y =mX +c
Where m = Slope
Slope of line 1 = 5
Slope of line 2 = -2
m1 is not equal to m2. Hence it is not parallel.
m1 × m2 is not equal to -1. Hence they are not perpendicular.
Answer:
31.82% probability that this day would be a winter day
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening
In this question:
Event A: Rain
Event B: Winter day
Probability of rain:
0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).
So
Intersection:
Rain on a winter day, which is 0.42 of 0.25. So
If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?
31.82% probability that this day would be a winter day