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Fudgin [204]
3 years ago
7

167÷2=83.5 how to solve

Mathematics
2 answers:
alexandr402 [8]3 years ago
4 0

Answer:

       8 3 5

2 / 1 6 7 0   = 167/ 2

Step-by-step explanation:

       8 3 5

2 / 1 6 7 0   = 167/ 2  When you place 8 above the 6 then 3 above the 7. you add another 0 next to 7 and input 5.  You show a remainder of 1 left of the zero to represent 1 of 0 as 2 divides 5 times into 10 it is not true 10 its just a remainder before the decimal).

gavmur [86]3 years ago
3 0

Step-by-step explanation:

162/2 (the same as 162÷2) =83.5

83.5+83.5=162

^

that was two times to add so we know for sure that 162/2=83.5. Theres no special way to solve it since its just dived by <em>two</em>. Its just 162÷2=83.5

Hope this helps.

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3 times a number is 54 less than the square of that number. Find the negative solution.
Pavel [41]

Answer:

x=-6

Step-by-step explanation:

Let x be the number

3x = x^2 -54

Subtract 3x

3x-3x = x^2 -3x-54

0 = x^2 -3x-54

Factor

What 2 numbers multiply to -54 and add to -3

-9*6 = -54

-9+6 = -3

0=(x-9) (x+6)

Using the zero product property

x-9=0    x+6=0

x=9  x=-6

The questions asks for the negative solution

x=-6

3 0
3 years ago
Will give 25 points if someone can answer this page
Studentka2010 [4]

Answer:

Domain = {1,2,3,4,5,6} and Range = {42,49,56,63,70,77The given function is :

y = 7x + 35

Where

x is no of members

y is the monthly cost

Your group has enough money for up to six members to joim fitness club. It means domain (the set of input values) are:

Domain = {1,2,3,4,5,6}

Put x = 1 to 6 one by one,

y = 7(1) + 35 = 42

y = 7(2) + 35 = 49

y = 7(3) + 35 = 56

y = 7(4) + 35 = 63

y= 7(5) + 35 = 70

y = 7(6) + 35 = 77

Range = {42,49,56,63,70,77}

ocabanga44 and 6 more users found this answer helpful

THANKS

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morgan1573

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4

answe

6 0
3 years ago
Read 2 more answers
HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

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3 years ago
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tigry1 [53]
The answer is B/2-4=9; b =$26
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If the ratio of sugar to flour is 10:3 and you use 70 ounces of sugar how many ounces of flour would you need to use?
olga_2 [115]
10+3=13
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So you would use 16 ounces of flour to 2 sig figs
6 0
3 years ago
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