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3 years ago

How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin and rolling a dice

2 answers:

6 0

You could get 2 different outcomes if you tossed a coin (head or tail) and 6 different outcomes if you rolled a dice (1-6). There would be 2 branches for tossing a coin and then 6 leaves on each for all the outcomes of rolling a dice so 6*2=12. There would be 12 leaves.

dolphi86 [110]3 years ago

4 0

The total number of outcomes of rolling a die = 6
The total number of outcomes of tossing a coin = 2

The total number of possible outcomes of executing both experiments is 6*2=12, which is also the number of leaves (end of the branch of a tree) on a tree diagram.

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What 3 digits are in the units period of 4,083,817

insens350 [35]

4, 3, 7 I hope this helped :)

6 0

3 years ago

A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the stu

Serggg [28]

<h2>Answer:</h2>

(B). $\frac{7}{12}$

<h2>Step-by-step explanation:</h2>

In the question,

Let the total number of geese be = 100x

Number of Male geese = 30% = 30x

Number of Female Geese = 70x

Let us say 'kx' geese migrated from these geese.

Number of migrated Male geese = 20% of kx = kx/5

Number of migrated Female geese = 4kx/5

So,

Migration rate of Male geese is given by,

$\frac{(\frac{kx}{5})}{30x}$

Migration rate of Female geese is given by,

$\frac{(\frac{4kx}{5})}{70x}$

So,

The ratio of Migration rate of Male geese to that of Female geese is given by,

$\frac{\left[\frac{(\frac{kx}{5})}{30x}\right]}{\left[\frac{(\frac{4kx}{5})}{70x}\right]}=\frac{350}{4\times 150}=\frac{7}{12}$

Therefore, the ratio of the rate of migration of Male geese to that of Female geese is,

$\frac{7}{12}$

Hence, the correct option is (B).

6 0

3 years ago

STANDARD DEVIATION

givi [52]

Answer:

0.1527

Step-by-step explanation:

Standard Deviation = √p × q/n

Reynolds: 63%

Bachmann: 37%

n = 100

Standard Deviation = √0.63 × 0.37/100

= √(0.02331)

= 0.1526761278

≈ 0.1527

4 0

3 years ago

Show work please thank you

ira [324]

1) 12 * 9 = 108 cm² - part 1
2) 12 - 3 - 3 = 6 cm
3) 6 * 4 = 24 cm² - part 2
4) 108 + 24 = 132 cm ² - the area.

3 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago