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Nookie1986 [14]
3 years ago
12

Sarah normally earns £600 each month. In December she is given a bonus of 1/5 of her normal pay. How much will she now earn this

month?
Mathematics
2 answers:
Zina [86]3 years ago
8 0
A salesman earns a base salary of $100 per week plus a 5% commission on all sales over 500. Find his total earnings in a week in which he sells r dollars worth of merchandise, with r being greater than 500
Anon25 [30]3 years ago
7 0

Answer:

She will earn 720 in December(Sorry, can't use the dollar sign.)

Step-by-step explanation:

1/5 of 600 is 120, so you want to add 120 to 600, which would be 720. Hope this helps!

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Combine the like terms
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8 1/4 pounds of carrots to make 6 carrot cakes. how many pounds of carrots does frank need to make one carrot cake.
jasenka [17]
The answer would be 1.4


6 0
3 years ago
What is the product? (-3s+2t)(4s-t)​
Step2247 [10]

Answer:

−12s2+11st−2t2

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
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SHOPPING Sergio, Boris, and Opa went shopping. If you add 4 dollars to the amount of money Sergio spent
Georgia [21]

Answer:

answer is 2

Step-by-step explanation:

if you create an equation: (s+4)x2 = boris          s-1x12 = opa

only one that only works out is 2        

               

6 0
2 years ago
Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

17.80% probability that all of them are wearing their seat belts.

3 0
3 years ago
Read 2 more answers
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