Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Solution:
Here we are given with the sides of the triangle as 5m, 16m and 5.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.
Hence no triangle can be made.
So the correct option is None.
Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Solution:
Here we are given with the sides of the triangle as 6m, 2m and 7m.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.
Hence one triangle can be formed.
So the correct option is one.
Given:
Joining fee = $28
Fee of each event = $4
To find:
Total cost for someone to attend 4 events.
Solution:
Let the number of events be x and total fee be y.
Fee for 1 event = $4
Fee for x events = $4x
Joining fee remains constant. So, the total fee is
Substitute x=4 in this equation.
Therefore, total cost of 4 events is $44.
Answer:
<h2>x = 5 , x = -3</h2>
Step-by-step explanation:
x^2 - 2x = 15
x^2 - 2x - 15 = 15 - 15 (Subtract 15 from both sides.)
x^2 - 2x -15 = 0 (Simplify.)
<em />
<em>Set up & solve for a quadratic formula</em>
<h3><em>* I will solve for your first x</em></h3>
2 + root 64 / 2x 1 = 2 + root 64 / 2
root 64 = 8
= 2 + 8 / 2
= 10 / 2
= 5
<em>To solve for the second, follow the same pattern/formula for the first that I used to get 5.</em>
The linear relationship in the form y = y = 3n + 72
What is linear relationship?
In statistics, a straight line of correlation between two variables is referred to as a linear relationship (or linear association). The mathematical equation y = mx + b can be used to represent linear relationships graphically.
<h3>According to the given information :</h3>
Each plant generates 34 oz of beans when she plants 30 stalks, and 33 stalks results in 33 oz of beans per plant, according to the information we have provided.
Equation 1 using data 1:
y = mn + b
Equation 1 using data 1:
30 = 34m + b
Equation 2 using data 2:
33 = 33m + b
Subtract equation 1 from equation 2:
33 - 30 = 34m + b - 33m - b
3 = m
m = 3
Rearrange equation 1 to solve for b:
b = 34(3) - 30
b = 102 - 30
b = 72
Therefore the equation becomes:
y = 3n + 72
The linear relationship in the form y = y = 3n + 72
To know more about linear relationship visit:
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