There is not enough info to answer this question.
Answer:
y = 10 when x = 5
Step-by-step explanation:
When x = 4, y = 8
Simplify. Divide 4 from both x and y
x = 4/4 = 1
y = 8/4 = 2
when x = 1, y = 2
Next, solve for when x = 5. Mutliply 5 to both x and y
x = 1 * 5 = 5
y = 2 * 5 = 10
y = 10 when x = 5
~
Answer:
The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]
Step-by-step explanation:
Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.
1. 6x+48 and 2(3x+24)
2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>
Bring in the first expression ~ <u>6x+48 and 6x+48 </u>
They are the same, so they are equivalent
2. 7x+21 and 2(5x+3)
2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6
Bring in the first expression ~ <u>7x+21 and 10x + 6</u>
They are NOT the same, so they are NOT equivalent
Answer:
It will be one-fourth the original size
Step-by-step explanation: