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Pavel [41]
3 years ago
8

What is the midpoint of the segment whose endpoints are 17,1 and -9,3

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
5 0
Easy ill tell u and then do a equation first sense it has - it means u have to subtract alright it goes like this. 17,1
                                                    9,3
                                                   --------
                                                    7,8
and this is ur answer as u see in my equation ur welcome only give me brainiest only if im right 
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Need to know a number bio for 5/8 break apart 3 ways
Fynjy0 [20]

Answer:

.208333... (as a fraction 5/24)

Step-by-step explanation:

5 divided by 8 = 0.625

.625 divided by 3 = .208333...

5/24

5*1 / 8*3 = 5/24. Therefore, 5/8 divided by 3 is equal to 5/24. In math you can flip the second denominator and numerator to multiply instead of dividing.

7 0
4 years ago
|a−b|−|c+d| , if a=−5; b=4; c=1; d=−3
Eva8 [605]

Answer:

7

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Find the inverse of the given function. f(x) = 7x – 4​
lukranit [14]

Hi there!

\large\boxed{y = \frac{x + 4}{7}}

f(x) = 7x - 4

Rewrite f(x) with y:

y = 7x - 4

Swap the x and y variables:

x = 7y - 4

Solve for y:

x + 4 = 7y

y = (x + 4)/7

3 0
3 years ago
It takes Joey 1/16 of an hour to write one thank you card how many cards can he write in 3/4 of an hour ?
svetoff [14.1K]

to write one thank you  card it takes 1/16 of an hour


1 card  * 3/4 hour  

--------       ---------      =         the hours cancel and you are left with cards

1/16 hour       1



3/4

------                                  copy dot flip

1/16      



3/4 * 16/1


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3 0
3 years ago
For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0
4 years ago
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