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Alekssandra [29.7K]
3 years ago
11

Mary Anne’s parakeet weighs 240g. Her cat weighs 3.1 kg. What is the difference, in grams, of the weights of her pets?

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

weights of parakeet = 240 g

Weight of cat = 3.1 kg = 3.1 * 1000 = 3100.0 g = 3100 g

difference = 3100 -240 = 2860 g

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Answer:

x = 6

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Step-by-step explanation:

Give triangle is a right triangle.

By applying sine ratio in the given triangle,

sin(60)° = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}

x = 6

Now we take the cosine ratio in the given triangle,

cos(60)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{y}{x}

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y = \frac{6}{2}=3

Therefore, x = 6 and y = 3 will be the answer.

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Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
2 years ago
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