75*.2=15
you would save $15
hope that helps
We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
Answer:
y=5/4 x
The slope is 5/4
Step-by-step explanation:
To solve this problem we need to find the equation of the line, y=mx+b
We've been given a table with several points, so we can use two of them to perform our calculus.
To obtain the slope we need to use the equation of slopes:
Where (x1,y1) =(4,5) and (x2,y2)=(8,10)
m= (10-5)/(8-4)=5/4
To obtain b we can use the point (x2,y2)=(8,10) in the equation.
10=5/4 *8 +b
b=0
Hence our line has the following equation:
y=5/4 x
no. No results should be presented in a fair and objective manner.
Gradient =
Change in Y
———————
Change in X
Change in Y is 18 - 14 = 4
Change in X is -20 - 30 = -50
Therefore the gradient is 4/-50 which is then simplified to - (2/25)