Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
At a thermoneutral ambient temperature, cooling either thermode increased oxygen consumption. In a cold environment, cooling either thermode increased the rate of oxygen consumption more than at a thermoneutral temperature. Heating either thermode tended to decrease oxygen consumption in a cold environment. 3.
Explanation:
The hydrocarbon which would most likely be an alkyne is COMPOUND W WHICH HAS A BOILING POINT OF -23.
This is because, among hydrocarbons, alkynes have the highest boiling points as a result of the triple bonds in their structures.
The boiling points of the other compounds are -103.7, -47 and -75; all these boiling points are lower than that of compound W.
The type of asexual reproduction which is being represented is definitely C. Fission, because according to the data above the entity has divided into two or more parts which is a characteristics for the fission.
<span>"Restriction enzymes would be used to cut the DNA into smaller pieces." is the statements best describes the first thing researchers need to manipulate dna. Before manipulation it is needed to isolate the desired DNA segment. Restriction enzyme can be also called as restriction endonuclease.</span>
