Suppose a class of 50 students has 20 males and 30 females. The insturctor will pick 1 (different) student to compete in 3 diffe
2 answers:
Answer:
(a)0.2908
(b)0.349
Step-by-step explanation:
Total Number of Students=50
Number of Male Students=20
Number of Female Students=30
Note that the selection is without replacement as each student selected is different. Also the student could be picked for any of Mathematics, Chemistry or English competitions in that order.
(a)Probability of Picking exactly one female student.
P(Exactly one Female)= P(FMM) OR P(MFM) OR P(MMF)
Where P(FMM) means a female is selected for Mathematics, Male for Chemistry and Male for English respectively.
P(FMM) OR P(MFM) OR P(MMF)
=0.2908
(b)Probability that at least 2 male students are selected.
P(at least 2 male students are selected) = P(FMM) OR P(MFM) OR P(MMF) OR P(MMM)
P(MMM) =0.0582
Recall from Part (a) that:
P(FMM) OR P(MFM) OR P(MMF) =0.2908
Therefore:
P(at least 2 male students are selected) =0.2908+0.0582 =0.349
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Answer:
a F
Step-by-step explanation:
Normally when converting to scientific notation, I would count how many digits I have to move the decimal dot to get it in between the number, in this case, 36.
If you start shifting the decimal dot to the right and count one every time you shift one digit and go all the way to between 3 and 6, you would count to 5. Since you are shifting to the right, the power of the 10 should be negative. Thus, the answer should be 3.6 × 10 which is F.