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2 years ago

After six games of crazy golf, Harvey's mean score was 39.5. After seven games his mean

Mathematics

1 answer:

Tasya [4]2 years ago

6 0

Answer:

Step-by-step explanation:

Basically dividing both of the outcome of the reliable equation, the outlier was 36

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Which word phrases can be modeled by the expression?

tensa zangetsu [6.8K]

A) (x÷7)-10
B) 7x -10
C) (x-10)÷7
D) (x÷7)-10

A and D are the same

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2 years ago

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Question<br> Round to the nearest ten: 1,078

natima [27]

Answer:

7 = 7 * 10 = 70

Step-by-step explanation:

7 0

1 year ago

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-5x-18y=-28 and -10x+9y=-11 solve elimination

Dmitry [639]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

Step-by-step explanation:

Given the equations

$-5x-18y=-28$

$-10x+9y=-11$

solving the system of the equation by elimination method

$\begin{bmatrix}-5x-18y=-28\\ -10x+9y=-11\end{bmatrix}$

$\mathrm{Multiply\:}-5x-18y=-28\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-10x-36y=-56$

$\begin{bmatrix}-10x-36y=-56\\ -10x+9y=-11\end{bmatrix}$

$-10x+9y=-11$

$-$

$\underline{-10x-36y=-56}$

$45y=45$

$\begin{bmatrix}-10x-36y=-56\\ 45y=45\end{bmatrix}$

solve 45y=5 for y:

$45y=45$

$\frac{45y}{45}=\frac{45}{45}$

$y=1$

$\mathrm{For\:}-10x-36y=-56\mathrm{\:plug\:in\:}y=1$

solve $-10x-36\cdot \:1=-56$ for x:

$-10x-36\cdot \:1=-56$

$-10x-36=-56$

Add 36 to both sides

$-10x-36+36=-56+36$

$-10x=-20$

$\frac{-10x}{-10}=\frac{-20}{-10}$

$x=2$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

5 0

2 years ago

Please help i’ll give brainliest

Luba_88 [7]

In a 45 - 45 - 90 right triangle, the hypotenuse is √2 · legs = hypotenuse, so legs= $\frac{\sqrt{5}}{\sqrt{2}}$ and to rationalize the denominator all we have to do is multiply the numerator and denominator by √2. $\frac{\sqrt{10}}{2}$ .

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2 years ago

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Please help with 3. 4. 5.

Eddi Din [679]

3.
$\text{The Triangle Sum Theorem:}\\m\angle A+m\angle B+m\angle C=180^o$
$x+2x-1+3x+1=180\\6x=180\ \ \ |:6\\x=30$
$x^o=30^o\\(3x+1)^o=(3\cdot30+1)^o=91^o\\(2x-1)^o=(2\cdot30-1)^o=59^o$
4.
$r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21$
$(r-6)^o=(21-6)^o=15^o\\(3r-3)^o=(3\cdot21-3)^o=60^o\\(5r)^o=(5\cdot21)^o=105^o$
5.
$\text{The Exterior Angle Theorem:}\\m\angle CAB+m\angle ABC=m\angle DCB$
$2g+9g=110\\11g=110\ \ \ |:11\\g=10$
$m\angle A=2\cdot10^o=20^o\\m\angle ACB=180^o-110^o=70^o\\m\angle B=9\cdot10^o=90^o$

4 0

2 years ago