After six games of crazy golf, Harvey's mean score was 39.5. After seven games his mean

Please help me help my daughter with question number 9

butalik [34]

So in a division equation you would take the dividend then divide it by the divisor (which in this case would be the 2) then after you divided you would get your quotient

4 0

3 years ago

For a two week period, John and Amanda had the following transactions occur to their checking account: a deposit of $1,644.50; c

Andru [333]

deposit of $1644.50 is (gain)

check written and deposit are (loses) subtracted

so total of 3 checks :- 190$ + 45$ + 7.50$ = 242.50$

total of 4 debit cards :- 30$ + 5.59$ + 7.20$ + 21.30$ = 64.09$

total lose amount ( credits + debits ) = 242.50 $ + 64.09$ = 306.59$

Ending balance = Total amount - total loses =

1644.50$ - 306.59 $ = 1337.91$

4 0

3 years ago

Hange 27 centimeters to millimeters.<br> A) 2.7 mm <br> B) 27 mm <br> C) 270 mm <br> D) 2700 mm

polet [3.4K]

Since 1 cm = 10 mm,

27 × 10 = 270

The answer is C.

7 0

3 years ago

A community center has an l shaped swimming pool that is 10 feet deep. What is the volume of the pool?

nataly862011 [7]

A because that is the maximam limet

8 0

3 years ago

Read 2 more answers

According to a 2014 Gallup poll, 56% of uninsured Americans who plan to get health insurance say they will do so through a gover

Airida [17]

Answer:

a) 24.27% probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange

b) 0.1% probability that in a random sample of 1000 people exactly 600 plan to get health insurance through a government health insurance exchange

c) Expected value is 560, variance is 246.4

d) 99.34% probability that less than 600 people plan to get health insurance through a government health insurance exchange

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and the binomial approximation to the normal.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The variance of the binomial distribution is:

$V(X) = np(1-p)$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

56% of uninsured Americans who plan to get health insurance say they will do so through a government health insurance exchange.

This means that $p = 0.56$

a. What is the probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange?

This is P(X = 6) when n = 10. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.56)^{6}.(0.44)^{4} = 0.2427$

24.27% probability that in a random sample of 10 people exactly 6 plan to get health insurance through a government health insurance exchange

b. What is the probability that in a random sample of 1000 people exactly 600 plan to get health insurance through a government health insurance exchange?

This is P(X = 600) when n = 1000. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 600) = C_{1000,600}.(0.56)^{600}.(0.44)^{400} = 0.001$