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3 years ago

Limited mobility may be a disadvantage of buying because the home is?

Mathematics

1 answer:

Serga [27]3 years ago

5 0

Difficult to sell

Explanation

There are many factors that limit the mobility and they are contributed by factors such as disease and accidental factors and there are many persons with disabilities

Many changes must be done with the layout of the home so if a house is designed with limited mobility it is very difficult to sell. Each and every different mobility homes have certain specifications and different accommodations.

The yards must be designed with mobility issues and they must create a stable and a wide pathway and these are much essential for wheel chair access

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Answer:

Step-by-step explanation:

we kno that a triangle is 180 degrees so we just add the first two angles

37 + 82 = 119

then subtract that from 180

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3 years ago

Read 2 more answers

What is the value of x? 27(x+4)=−6

jonny [76]

First you need to use the distributive property: 27(x+4)=-6
27x+108=-6
then you need to subtract 108 from -6 to
get x alone. 27x= 102

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3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: