Answer:
B. 225 π sq. units
Step-by-step explanation:
the diameter of circle = √18²+24²
=√324+576=√900 = 30
the radius = ½×30=15
the area of circle =
π × 15² = π × 225 = 225 π sq. units
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Answer:
9. No
10. Yes
Step-by-step explanation:
The first one is not, since you have (3, 3) and (3, 9). In a function, each x maps to a single y.
The second one is since every x appears only once.
Answer:
Think it is A as 4x20=80.
<em><u>ANSWER</u></em>
Let the width be y
2(L + W) = Perimeter
2(2y - 5cm + y) = 62cm
(2×2y) + (2×-5cm) + (2×y) = 62cm
4y + - 10cm + 2y = 62cm
4y - 10cm + 2y = 62cm
4y + 2y - 10cm = 62cm
6y - 10cm + 10cm = 62cm + 10cm
<u>6</u><u>y</u> = <u>7</u><u>2</u><u>c</u><u>m</u>
6 6
y = 12cm
<em><u>WIDTH</u></em>
= y
= 12cm
<em><u>LENGTH</u></em>
= 2y - 5cm
= 2×y - 5cm
= 2×12cm - 5cm
= 24cm - 5cm
= 19cm
<em><u>Providence</u></em>
19cm + 19cm + 12cm + 12cm = 62cm which is the perimeter
