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Archy [21]
3 years ago
14

In daily life, we see many cases of people who are caught misrepresenting things and soon tehreafter are excused and accepted by

their contemporaries. How is this different in science?
Social Studies
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

Yes, its very much true that in our daily life, we say something to someone and he r she can misunderstood it or perceive it in a totally different way but when it comes to science the case is totally different. In order to stand this statement we have to look deeper into the factors which make it so.

In our real life, we deal with the things on the basis of our own experience or perceptions, we see and feel the things on the base of our own frame of reference, we judge the things as per our own feelings which certainly are different from other person. Why this is so? This happens because each and every single person has its own context through which he or she lives in this wold, for example, one person can find $100 enough for a whole week, whereas, £1000 would not be sufficient for another person even for single day. One person's luxury will only be having one KFC burger in a whole week but for another person the same burger will be very ordinary thing. That's why different persons act to the same situation in a different way because there are no clear cut, defined, written in black and white rules but when it comes to science, there are perceptual definite rules. Water has a specific formula that two atoms of hydrogen and one of oxygen will make water in every part of the word. Therefore, that's the reason why people misunderstood things of daily life while same thing don't happen in science.

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<h3>Remainder theorem</h3>

If F(x) is a polynomial and it is divided by C

to give Q and a remainder of D

Then,

Polynomial = (Quotient × divisor) + remainder

F(x) = (Q × C ) + D

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Polynomial = (Quotient × divisor) + remainder

P(x) = [Q(x) × (x + 3)] + 7

P(3)= [Q(3) × (x + 3)] + 7

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<h3>2. How to determine the value of P(–3)</h3>
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Polynomial = (Quotient × divisor) + remainder

P(x) = [Q(x) × (x + 3)] + 7

P(–3)= [Q(–3) × (–3 + 3)] + 7

P(–3) = [Q(–3) × 0] + 7

P(–3) = 0 + 7

P(–3) = 7

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