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3 years ago

When u wake up in the morning and you see few on the ground, where did it come from, and how did it form?

Physics

1 answer:

Pavlova-9 [17]3 years ago

4 0

Answer:

If you mean dew not few, than the cause of dew is condensation.

Explanation:

At night, the air temperature gets lower, causing the water in its vapor state in the air to turn to the liquid state.The water will gather on most solid surfaces, especially grass and other plants. The dew came from the water in the air.

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The mass of the products (solid and gaseous) of a fire is the same as the mass of the fuel and oxygen consumed in the fire.

deff fn [24]

Answer:

I think it might be true but I am not 100%

Explanation:

6 0

3 years ago

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The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy ne

Allisa [31]

Answer:

17 * 10^5 J

Explanation:

From;

H= mcΘ

where;

m = mass of water = 5.0 Kg

c = heat capacity of water = 4 200 J/Kg °C

Θ = temperature rise = 100 °C - 20 °C = 80°C

Substituting values;

H = 5 * 4 200 * 80

H = 17 * 10^5 J

4 0

3 years ago

What information do you need to describe an object's location

stira [4]

longitude and latitude<span />

4 0

3 years ago

Two point charges exert a 6.10 N force on each other. What will the force become if the distance between them is increased by a

anzhelika [568]

Answer:

0.0953125 N

Explanation:

Applying,

F = kq'q/r²................. Equation 1

Where F = electrostatic force, k = coulomb's constant, q' and q = first and second charge respectively, r = distance between the charge.

From the equation,

If both charges remain constant,

Therefore,

F = C/r²

C = Constant = product of the two charge(q' and q) and k

Fr² = F'r'²................ Equation 2

From the question,

Given: F = 6.10 N

Assume: r = x m, r' = 8x

Substitute these value into equation 2

6.1(x²) = F'(8x)²

F' = 6.1/64

F' = 0.0953125 N

Hence the new force will become 0.0953125 N

5 0

3 years ago

m_Cu * sh_CuA system consists of a copper tank whose mass is 13 kilogram , 4 kilogram of liquid water, and an electrical resisto

notsponge [240]

Answer:

T₂ = 49.3°C

Explanation:

Applying law of conservation of energy to the system we get the following equation:

Energy Supplied by Resistor = Energy Absorbed by Tank + Energy Absorbed by Water

E = mC(T₂ - T₁) + m'C'(T'₂ - T'₁)

where,

E = Energy Supplied by Resistor = 100 KJ = 100000 J

m = mass of copper tank = 13 kg

C = Specific Heat of Copper = 385 J/kg.°C

T₂ = Final Temperature of Copper Tank

T₁ = Initial Temperature of Copper Tank = 27°C

T'₂ = Final Temperature of Water

T'₁ = Initial Temperature of Water = 50°C

m' = Mass of Water = 4 kg

C' = Specific Heat of Water = 4179.6 K/kg.°C

Since, the system will come to equilibrium finally. Therefor: T'₂ = T₂

Therefore,

(100000 J) = (13 kg)(385 J/kg.°C)(T₂ - 27°C) + (4 kg)(4179.6 J/kg.°C)(T₂ - 50°C)

100000 J = (5005 J/°C)T₂ - 135135 J + (16718.4 J/°C)T₂ - 835920 J

100000 J + 135135 J + 835920 J = (21723.4 J/°C)T₂

(1071055 J)/(21723.4 J/°C) = T₂

8 0

3 years ago