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uysha [10]
2 years ago
11

Objects 1 and 2 attract each other with a electrostatic force

Physics
1 answer:
algol132 years ago
5 0

Answer:

72.0 + 72.0 whatever you get for that answer

Explanation:

I don't know what else to put

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Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of v=0.8c
Studentka2010 [4]

Answer:

30.96 m

Explanation:

If the particle has a lifetime of 129 ns as measured by observer A, and has a speed of 0.8c as measured by observer A, the distance between the markers will be:

d = v * Δt

v = 0.8*c = 0.8 * 3e8 = 2.4e8

Δt = ζ = 129 ns = 1.29e-7 s

d = 2.4e8 * 1.29e-7 = 30.96 m

This is the distance as measured by observer A.

3 0
3 years ago
A metal bar has a volume of 32 cm3. The mass of the bar is 256 g. What is the density of the metal? A. 290 g/cm3 6 B. 8,200 g/cm
lina2011 [118]

Answer:

espera que te sirva

7 0
2 years ago
Along the frictionless path you have chosen, the main force(s) acting on the puck after receiving the kick is (are):
Vaselesa [24]
Gravity, and Normal. Check the comments for why Applied isn't one.
5 0
3 years ago
Three-fourths of the elements on the
77julia77 [94]

Answer:

b

Explanation:

because the metalloids are the thing in the middle

8 0
3 years ago
4
Zigmanuir [339]

(a) The object moves with uniform velocity from A to B.

(b) The object moves with constant velocity from B to C.

(c) The object moves with increasing velocity from C to D.

<h3>Velocity of the object from point A to B</h3>

V(A to B) = (6 - 0)/(4 - 0) = 1.5 m/s

<h3>Velocity of the object from point B to C</h3>

V(B to C) = (6 - 6)/(11 - 4) = 0 m/s

<h3>Velocity of the object from point C to D</h3>

V(C to D) = (7 - 6)/(12 - 11) = 1 m/s

final velocity = 1 + 1.5 m/s = 2.5 m/s

Thus, we can conclude the following;

The object moves with uniform velocity from A to B.

The object moves with constant velocity from B to C.

The object moves with increasing velocity from C to D.

Learn more about velocity here: brainly.com/question/6504879

#SPJ1

4 0
2 years ago
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