The circuit is in parallel connection
Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3
From the information given,
R1 = 5
R2 = 2
R3 = 4
1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20
Req = 20/19 = 1.053 ohms
I = V/R
Given that V = 12,
Current flow through circuit = 12/1.053 = 11.4 A
I1 + I2 + I3 = 11.4
I1 = 12/5 = 2.4 A
I2 = 12/2 = 6 A
I3 = 12/4 = 3A
The answer is the second choice
Answer:
1.67×10^-11 N
Explanation:
m1 = 0.13kg
m2 = 0.34kg
d = 0.42m
G = 6.674 × 10 ^−11
F = Gm1m2/r²
F= (6.674 × 10^ −11×0.13×0.34)/(0.42)²
F = 1.67×10^-11 N
P1.5.3 thats what i got........... hope its right not sure though
The answer is:
It can be disruptive to the whole banking system.
