Natural sources of light include our sun and other stars, where the source of energy is nuclear energy (recall that the moon does not produce light but merely reflects sunlight), lightning, where the source is electrical, and fire, where the energy source is chemical.
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The units for G must be ![[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Explanation:
The magnitude of the gravitational force between two objects is given by:

where
F is the force
G is the gravitational constant
are the masses of the two objects
is the separation between the objects
We know that:
- The units of F are Newtons (N)
- The units of
are kilograms (kg) - The units of
are metres (m)
So, we can rewrite the equation in terms of G, to find its units:
![G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=G%3D%5Cfrac%7BFr%5E2%7D%7Bm_1%20m_2%7D%3D%5Cfrac%7B%5BN%5D%5Bm%5D%5E2%7D%7B%5Bkg%5D%5Bkg%5D%7D%3D%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Learn more about gravitational force:
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If the kinetic energy of each ball is equal to that of the other,
then
(1/2) (mass of ppb) (speed of ppb)² = (1/2) (mass of gb) (speed of gb)²
Multiply each side by 2:
(mass of ppb) (speed of ppb)² = (mass of gb) (speed of gb)²
Divide each side by (mass of gb) and by (speed of ppb)² :
(mass of ppb)/(mass of gb) = (speed of gb)²/(speed of ppb)²
Take square root of each side:
√ (ratio of their masses) = ( 1 / ratio of their speeds)²
By trying to do this perfectly rigorously and elegantly, I'm also
using up a lot of space and guaranteeing that nobody will be
able to follow what I have written. Let's just come in from the
cold, and say it the clear, easy way:
If their kinetic energies are equal, then the product of each
mass and its speed² must be the same number.
If one ball has less mass than the other one, then the speed²
of the lighter one must be greater than the speed² of the heavier
one, in order to keep the products equal.
The pingpong ball is moving faster than the golf ball.
The directions of their motions are irrelevant.
Answer:
i. 0.34
ii. 0.4
iii. 1700 w/m²
iv. 2211.36 w/m²
Explanation:
Given that
Irradiation of the plate, G = 2500 w/m²
Reflected rays, p = 500 w/m²
Emissive power, E = 1200 w/m²
See attachment for calculations