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Cloud [144]
3 years ago
11

The exam scores (out of 100 points) for all students taking an introductory Statistics course are used to construct the followin

g boxplot. Based on this boxplot, the interquartile range is closest to 50. 25. 80. 10.
Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer:

The inter quartile range is 55

Step-by-step explanation:

<u>Interquartile range</u>:-

<u>Definition</u>:-

The inter quartile range is the difference between the upper (Q3) and lower(Q1) quartiles, and describes the middle  50% of values when ordered from lowest to highest.

Interquartile range = higher quartile - lower quartile

given data 50.25.80.10

write the ascending order 10 25 50 80

Step:-1

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is

({\frac{n+1}{2} })^{th}observations

Step2:-

The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is even, then the median is ({\frac{n}{2} })^{th}

({\frac{n+1}{2} })^{th}

In given data the number of observations is '4'(even)

If the number of observations is even, then the median is ({\frac{n}{2} })^{th}

({\frac{n+1}{2} })^{th}

median is ({\frac{4}{2} })^{th} is 2 observations and ({\frac{4+1}{2} })^{th} is 2.5 observations.

so we have to select average of these two observations.

therefore the median is '3' observation

median of the given data = 50

<u>Step:3</u>

Interquartile range = higher quartile - lower quartile

                                  = 80-25

                                  =55

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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa
tatuchka [14]

Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

y=x\left(0.15-0.001x\right)

y=0.15x-0.001x^2

To find maximum height of second puck

y'=0.15-0.002x

Equate the derivative equals to 0

0.15-0.002x=0

\frac{0.15}{0.002}=x

75 = x

At x = 75

y=0.15(75)-0.001(75)^2=5.625

So, The maximum height of second puck is greater than  first puck

So, Second puck travels farther

5 0
3 years ago
Sammy rides his bike to school and to pick up his sister at her school. He rides 4 miles round trip to his school. To his sister
KatRina [158]

Answer: 300

Step-by-step explanation: First of all calcute how much per day, which is 5 miles. Then by 5 days which is 25. Now by 12 which is 300.

Hope this helped :)

4 0
3 years ago
What is the interquartile range of a data set? <br> what does the IRQ tell you about a data set?
Naddik [55]

Answer:

I would help you... But I think that you are supposed to have a picture and there is no picture.

4 0
3 years ago
How many times can 8 go into 60
nignag [31]

The correct answers are:

(1) If EXACT number is required, then 7.5.

(2) If multiple of 8 is required then the answer will be 7 times with a remainder of 4.

Explanation:

First you need to express it in the form of equation to make things simpler as follows:

8 * y = 60

We need to find y; to do so, divide 60 by 8:

y = \frac{60}{8}

y = 7.5

Now if you want to find the whole number, then the answer will be 7 times, with 4 left over.

6 0
3 years ago
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