It would be ASA(angle side angle)
if 2 angles and an included side are congruent, then the two triangles are congruent.
A = (1/2)bh [b = 10 m, h = 6 m]
A = (1/2) * 10 * 6 = 30 m²
Given that
The length of the rectangle 4cm and the breadth is 3cm
Area of rectangle= length * breadth
Area= 4*3
= 12cm^2
Hope it helped
Answer:
C.
Step-by-step explanation:
You are given 3x-4y<16 and we want to see which of the ordered pairs is a solution.
These ordered pairs are assumed to be in the form (x,y).
A. (0,-4)
?
3x-4y<16 with (x=0,y=-4)
3(0)-4(-4)<16
0+16<16
16<16 is not true so (0,-4) is not a solution of the given inequality.
B. (4,-1)?
3x-4y<16 with (x=4,y=-1)
3(4)-4(-1)<16
12+4<16
16<16 is not true so (4,-1) is not a solution of the given inequality.
C. (-3,-3)?
3x-4y<16 with (x=-3,y=-3)
3(-3)-4(-3)<16
-9+12<16
3<16 is true so (-3,-3) is a solution to the given inequality.
D. (2,-3)?
3x-4y<16 with (x=2,y=-3)
3(2)-4(-3)<16
6+12<16
18<16 is false so (2,-3) is not a solution to the given inequality.
Length = x
width = y
y = 16
x = 2y
x = 2(16)
x = 32
perimeter = 2x + 2y
= 2(32) + 2(16)
= 64 + 32
= 96
