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3 years ago

Solve for n.3/4n = 1 3/4n - 18

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

3/4n=1 3/4n-18

3/4n=7/4n-18

3/4n-7/4n=7/4n-18-7/4n

-n=-18

-n/-1=-18/-1

N=18

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3 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

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Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

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Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

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Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

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Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

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2 years ago

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notsponge [240]

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Then, with 45 extra, we add that to the equation:

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Answer: F(x) = 225x + 45

Credit to: @2Educ8

+ = <3

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3 years ago