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3 years ago

If x equals 12 and y equals 9 find the value of 2 x - 2y

Mathematics

1 answer:

Genrish500 [490]3 years ago

4 0

2 ( 12) - 2 (9)

24 - 18

6 answer

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Write 2 to the 100th power as an exponent with a base of: 32

neonofarm [45]

2^5x2^100

also known as 1

6 0

3 years ago

The factors of the quadratic function g(x) are (5x – 1) and (x + 4). What are the solutions to the equation g(x) = 0?

Cerrena [4.2K]

Answer:

The solutions to the equation are $x = \frac{1}{5}$ and $x = -4$

Step-by-step explanation:

The factors of the quadratic function g(x) are (5x – 1) and (x + 4).

This means that:

$g(x) = 0$

$(5x - 1)(x + 4) = 0$

$5x - 1 = 0$

$5x = 1$

$x = \frac{1}{5}$

And

$x + 4 = 0$

$x = -4$

The solutions to the equation are $x = \frac{1}{5}$ and $x = -4$

7 0

3 years ago

153 is .9% of what number?

victus00 [196]

If you mean 9% of 153 your answer is 13.77

7 0

3 years ago

observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

agasfer [191]

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

$2xy =6.....(a)\\\\x-y= 3.....(b)\\\\$

After solve equation (a) we get

$\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\$

After solve equation (b) we get

$\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\$

put the value of x in to equation (x)

$(3+y)y = 3\\$

$y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\$

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

5 0

3 years ago

Determine the end behavior of each rational function below. <br> f(x) = 7x5 − 3x + 1 / 4x3 + 2

Svetllana [295]

Answer:

When x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ +∞

Step-by-step explanation:

Hi there!

First, let´s write the function:

f(x) = (7x⁵ - 3x +1) / (4x³ + 2)

When x ⇒ +∞

f(x) ⇒ (7x⁵ - 3x) / 4x³ because (7x⁵ - 3x)>>>1 and 4x³>>>2 we can neglect those constants.

f(x) ⇒7x⁵/4x³ - 3x/4x³

f(x) ⇒ 1.75x² - 0.75/x² (0.75/x² ⇒ 0 because a number divided by a very big number is approximately zero). Then:

f(x) ⇒ 1.75x² ⇒ +∞

When x ⇒ -∞

f(x) ⇒ 1.75x² = +∞ (because x² is always positive)

Then, when x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ +∞

8 0

3 years ago