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2 years ago

Translate and solve. 17. The absolute value of three times a number, n, is greater than 15.

Mathematics

1 answer:

castortr0y [4]2 years ago

3 0

Answer:

3n>15

Step-by-step explanation:

So basically, this three times a number, 3n, is greater than 15. So, this is 3n>15.

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Please helpppppp

melomori [17]

Given Information:

Years = t = 35

Semi-annual deposits = P = $2,000

Compounding semi-annually = n = 2

Interest rate = i = 6.5%

Required Information

Accumulated amount = A = ?

Answer:

Accumulated amount = $515,827

Step-by-step explanation:

The future value of amount earned over period of 35 years and interest rate 6.5% with semi-annual deposits is given by

FV = PMT * ((1 + i/n)^nt - 1)/(i/n))

Where

n = 2

i = 0.065

t = 35

FV = 2000*((1 + 0.065/2)^2*35 - 1)/(0.065/2))

FV = 2,000*(257.91)

FV ≈ $515,827

Therefore, Anthony will have an amount of $515,827 when he retires in 35 years.

6 0

3 years ago

C more than 5 as an algebraic expression??????

Natasha_Volkova [10]

C more than 5 as an algebraic expression c>5

3 0

2 years ago

Read 2 more answers

Caluculate the quotient <br> 8/9 divided by 4/9

Svet_ta [14]

8/9 / 4/9
=(8/9)*(9/4) Multiply by second reciprocal
=(2/1)*(1/1) Cross reduce
=2 Multiply

6 0

3 years ago

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean