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3 years ago

5 1/5 divided by -13/15

Mathematics

2 answers:

zepelin [54]3 years ago

5 0

Look up this site called calculator soup it gives great answers

bixtya [17]3 years ago

4 0

Your answer will be -3/15

HOPE IT HELPED!

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

WILL MARK BRAINLIEST AND GIVE 100 POINTS! WILL REPORT IF INCORRECT

grigory [225]

please refer to this image

please don't report this answer if it is wrong

but if its correct so please mark me as brainlist

5 0

2 years ago

Estimate the sum of 279 and 217

Shalnov [3]

280 + 220 = 500 is the answer

6 0

3 years ago

Given the replacement set {0,1,2,3,4} solve 4x - 5 = 11

kicyunya [14]

4x - 5 = 11
4x = 11 + 5 = 16
4x = 16
Divide by 4 from both sides
X = 4

7 0

3 years ago

Raul has been offered three different jobs and must choose which one to accept. One of the factors he is considering is the pay

chubhunter [2.5K]

Answer:

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

Step-by-step explanation:

Given that Raul would work 50 weeks of the year,

40 hours each week,

5 days each week,

and he would receive a 1-hour lunch break each day.

Pay rate for Job A = $35,000 / year

For Job B:

Pay rate = $15 / hour

He will work 40 hours each week.

As he works 5 days a week, so in 1 day he will work 40/5 = 8 hours.

He would receive a 1-hour break each day, for which he will not be paid, so he will receive a payment for 8-1=7 hours.

So, payment for 1 day = $15 x 7 = $105

As he works 5 days a week, so payment for 1 week = $105 x 5 = $525

As he works 50 weeks a year, so payment for 1 year = $525 x 50 = $26250.

So, the pay rate by Job B = $26250 /year

For Job C:

Pay rate = $750 / week

As he works 50 weeks a year, so payment for 1 year = $750 x 50 = $37500.

So, the pay rate by Job C = $37500 /year

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

8 0

2 years ago