All categories

2 years ago

Factorise fully 18x+9

Mathematics

1 answer:

galina1969 [7]2 years ago

5 0

Answer: 9 (2x + 1)

Step-by-step explanation: i hope i helped

You might be interested in

Determine the equation for the parabola graphed below?

polet [3.4K]

Answer:

y = $\frac{1}{2}$ x² - 2x + 1

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

From the graph (h, k) = (2, - 1), thus

y = a(x - 2)² - 1

To find a substitute a point on the curve (0, 1) into the equation

1 = 4a - 1 ( add 1 to both sides )

4a = 2 ( divide both sides by 4 )

a = $\frac{2}{4}$ = $\frac{1}{2}$ , hence

y = $\frac{1}{2}$ (x - 2)² - 1 ← in vertex form

Expand the factor and simplify

y = $\frac{1}{2}$ (x² - 4x + 4) - 1

= $\frac{1}{2}$ x² - 2x + 2 - 1

= $\frac{1}{2}$ x² - 2x + 1 ← in standard form

8 0

2 years ago

Read 2 more answers

A driver runs over a nail, puncturing the tire without causing a leak. The position of the nail in the tire, with relation to th

Elina [12.6K]

Answer: period

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say E occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, n = 20.

Number of defective electric toothbrushes is, x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0

2 years ago

Find the percent from 14 to 40

mojhsa [17]

Answer:

Step- by- Step Explanation

3 0

2 years ago

What is the domain of y=3^x-2 +1

mel-nik [20]

Answer:

x∈R

Step-by-step explanation:

4 0

3 years ago