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Crank
4 years ago
13

Move the man steadily to the right towards the house. Describe his position. (Constant? Changing? Negative? Positive?)

Physics
1 answer:
Vinvika [58]4 years ago
5 0
The man has a constant velocity/speed but a changing position towards the right which would usually be considered a positive direction.
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Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball
Sidana [21]

Answer:

255.4 N/m

Explanation:

We can consider the system eyeball-attached to the musculature as a mass-spring system in simple harmonic motion, whose frequency of oscillation is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where in this case, we know:

f = 29 Hz is the frequency of oscillation

k is the spring constant, which is unknown

m = 7.7 g = 0.0077 kg is the mass of the eyeball

Solving the equation for k, we find the spring constant of the musculature attached to the eyeball:

k=(2\pi f)^2 m=(2 \pi (29 Hz))^2 (0.0077 kg)=255.4 N/m

6 0
3 years ago
A car traveling from rest to a velocity of 7.0 m/s accelerates uniformly at the rate of 0.80 m/s2. What is its tr. 31
Phoenix [80]

Answer:

54mph

Explanation:

3 0
4 years ago
Katrina inserts a key into her car’s ignition. She turns the key, putting her car into ignition mode. In this mode, some energy
Anestetic [448]

Answer: The option (C) is correct.

Explanation:

Ignition is the process in which the fuel is made to start burn. In car's ignition, it is the part where the key is turned so that the engine may get start.

The fossil fuel which is used in the car's engine is petroleum. Therefore, the chemical energy is used to allow the fuel to burn and move the car.

4 0
3 years ago
Read 2 more answers
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
Which of the following is the correct unit to measure the current in a radio?
CaHeK987 [17]

Answer:

watts

Explanation:

3 0
3 years ago
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