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Alinara [238K]
4 years ago
6

Nio conducts a science experiment. He puts yeast into a bottle with water and sugar, and then caps the bottle with a balloon. He

returns two hours later and notices there are bubbles on the surface of the mixture in the bottle and that the balloon has inflated, but there are no other apparent changes.
What most likely happened?

A: a non-chemical change, because there are no indicators of chemical changes taking place
B: a chemical change, because the mixture changed color
C: a chemical change, because a gas was produced
D: a non-chemical change, because the changes that occurred are reversible
Physics
2 answers:
KATRIN_1 [288]4 years ago
3 0

Answer: Option (C) is the correct answer.

Explanation:

When yeast is added into a bottle with water and sugar then after some time yeast becomes activated. This results in the formation of a chemical change as bubbles are formed on the surface of the mixture in the bottle.

This indicates that a gas has been released due to the chemical change.

Thus, we can conclude that most likely a chemical change has occurred because a gas was produced.

Triss [41]4 years ago
3 0

Answer:

C

Explanation:

I took de test

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You are riding a broomstick and see a golden ball hovering motionless 30 meters directly in front
Alisiya [41]

You should fly at an angle of 14.0^{\circ}

Explanation:

The motion of the ball is a free fall motion, so the vertical displacement of the ball (in negative directions) is given by

y=\frac{1}{2}gt^2

where

g=9.8 m/s^2 is the acceleration due to gravity

t is the time

The horizontal distance you have to cover to catch the ball is

x = 30 m=d

The vertical and horizontal displacement form a right triangle, so that we can write

tan \theta = \frac{y}{x}

where \theta is the direction of your motion. Substituting,

tan \theta = \frac{gt^2}{2d} (1)

We also know that the horizontal position of the person at time t is

x(t) = v cos \theta t

And so, for the time t at which the person catches the ball,

d=v cos \theta t\\t=\frac{d}{v cos \theta}\\t^2=\frac{d^2}{v^2 cos^2 \theta}

Substituting this expression into (1),

tan \theta = \frac{g}{2d} \frac{d^2}{v^2 cos^2 \theta}\\2 tan \theta cos^2 \theta = \frac{gd}{2v^2}

And using

tan \theta = \frac{sin \theta}{cos \theta}, 2sin \theta cos \theta = sin(2\theta)

we find:

sin (2\theta) = \frac{gd}{v^2}=\frac{(9.8)(30)}{25^2}=0.470\\2\theta = sin^{-1}(0.470)=28.0^{\circ}\\\theta=\frac{28}{2}=14.0^{\circ}

Learn more about free fall motion:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

4 0
3 years ago
The decrease in the intensity of light over distance, such as with increasing depth in water, is known as ______.
Anna [14]

Answer:

Attenuation

Step By step Explanation:

The decrease in the intensity of light over distance, such as with increasing depth in water, is known as ______.

It is called attenuation.

The decraese in the amplitude of the signals is called attenuation.

5 0
3 years ago
What is the formula for calculating the efficiency of a heat engine? Answers:
Setler [38]
Efficiency of heat engine is determined by the ratio of difference in temperature of cold from hot reservoir to the temperature of hot reservoir over temperature of hot reservoir.
7 0
3 years ago
An object is pulled with two forces, 10 N northward and 15 N southward. The direction of the net force is to the An object is pu
ValentinkaMS [17]

Answer:

check image

Explanation:

For any question related to newons law of motion first draw the free body diagram(FBD),

7 0
4 years ago
Mercury is 0.39 AU from the sun. What is its distance from the sun in kilometers?
qaws [65]

Answer:

0.39AU = 58344000 [km] or 58.500.000 [km]

Explanation:

This is a problem that consists simply in converting units:

AU = astronomic unit

1 [AU] = 1.496*10^{8} [km]\\0.39 [AU] = x\\\\Therefore\\x = \frac{0.39*1.496*10^{8} }{1} \\x = 58344000[km]

8 0
3 years ago
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