PLEASE HELP!!!<br><br> Both Transverse and Longitudinal Waves transmit _______ and not _____

A man 6 feet tall walks at a rate of 6 feet per second away from a light that is 15 feet above the ground.

Tems11 [23]

Answer:(a)10 ft/s

(b)4 ft/s

Explanation:

Given

height of light $=15 feet$

height of man $=6 feet$

$\frac{\mathrm{d} x}{\mathrm{d} t}=6 ft/s$

From diagram

$\frac{15}{y}=\frac{6}{y-x}$

$5(y-x)=2y$

$3y=5x$

differentiate both sides

$3\times \frac{\mathrm{d} y}{\mathrm{d} t}=5\times \frac{\mathrm{d} x}{\mathrm{d} t}$

Tip of shadow is moving at the rate of

$\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{5}{3}\times 6=10 ft/s$

(b)rate at which length of his shadow is changing

Length of shadow is $y-x$

differentiating w.r.t time

$\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=\frac{\mathrm{d} y}{\mathrm{d} t}-\frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=10-6=4 ft/s$

7 0

3 years ago

Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vert

chubhunter [2.5K]

Answer:

362.41 km/h

Explanation:

F = Force

m = Mass = 84 kg

g = Acceleration due to gravity = 9.81 m/s²

C = Drag coefficient = 0.8

ρ = Density of air = 1.21 kg/m³

A = Surface area = 0.04 m²

v = Terminal velocity

F = ma

$F=\frac{1}{2}\rho CAv^2\\\Rightarrow mg=\frac{1}{2}\rho CAv^2\\\Rightarrow v=\sqrt{2\frac{mg}{\rho CA}}\\\Rightarrow v=\sqrt{2\frac{20\times 9.81}{1.21\times 0.8\times 0.04}}\\\Rightarrow v=100.66924\ m/s$

Converting to km/h

$100.66924\times 3.6=362.41\ km/h$

The terminal velocity of the stone is 362.41 km/h

5 0

2 years ago

Read 2 more answers

Which image shows an example of the strong nuclear force in action?

dusya [7]

i think this is the incomplete page that you are showing but the answer is

:-

6 0

3 years ago

When work is done on a spring to stretch it, elastic potential energy is stored in the spring.

aniked [119]

Explanation:

I think its true

hope it helps

6 0

2 years ago

Analyze the chemical reaction below

Tcecarenko [31]

Answer:

Explanation:

The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .

In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass

6 0

2 years ago

PLEASE HELP!!! Both Transverse and Longitudinal Waves transmit _______ and not ______.

PLEASE HELP!!! Both Transverse and Longitudinal Waves transmit _ and not .