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Studentka2010 [4]
3 years ago
12

Can Some1 help??

Physics
1 answer:
anyanavicka [17]3 years ago
7 0
What type of problem it is
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A current of 02kA is traveling through a circularly looped wire. The wire makes 35 turns around an induced magnetic field of 8 9
PIT_PIT [208]

Answer:

The radius of the loop is 4.94\times10^{5}\ m

Explanation:

Given that,

Current = 0.2kA = 200 A

Number of turns = 35

Magnetic field = 8.9 nT

We need to calculate the radius of one loop

Using formula of magnetic field

B=\dfrac{N\mu_{0}I}{2r}

r=\dfrac{N\mu_{0}I}{2B}

Where, I = current

N = number of turns

B = magnetic field

r = radius

Put the value into the formula

r=\dfrac{35\times4\pi\times10^{-7}\times200}{2\times8.9\times10^{-9}}

r =494183.11\ m

r=4.94\times10^{5}\ m

Hence, The radius of the loop is 4.94\times10^{5}\ m

3 0
3 years ago
Lenny loves physics and math. In which Energy career pathway would these interests be the most helpful?
vazorg [7]

Answer:

it is D

Explanation:

cause i took the test

3 0
4 years ago
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How much force is needed to stop a 80-kg football player if he decelerates at 5 m/s2
kiruha [24]
According to Newton's 2nd law of motion, F =ma = 80x5 = 400N.
6 0
4 years ago
if v=5.00 meters/second and makes an angle of 60 degrees with the negative direction of the y-axis, calculate the possible value
lora16 [44]

The answer is both 5sin(60)=4.33 and -5sin(60)=-4.33

5 0
3 years ago
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A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th
Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0
3 years ago
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