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Luba_88 [7]
3 years ago
10

A map is scaled so that 1 cm on the map is equal to 15 actual miles. If two cities on the map are 10 cm apart, proportion would

you use to solve the problem?
Mathematics
2 answers:
Daniel [21]3 years ago
7 0

Answer:

 

A. the fraction of map over actual equals one-fifteenth equals the fraction 10 over x

 

B. the fraction of map over actual equals the fraction 15 over 1 equals the fraction 10 over x

 

C. the fraction of map over actual equals the fraction 15 over 1 equals the fraction x over 10

 

D. the fraction of map over actual equals the fraction x over 15 equals the fraction 10 over 1



Step-by-step explanation:I don't know the answer I'm just hoping someone can see the possible answers so they can answer this question.


OLga [1]3 years ago
6 0
Is there answer choices?

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Six times a number is 45 greater than the the product of the number and -3. Find the number.
blagie [28]

Let us try to formulate the expressions one by one.

let the number be x.

Step 1:

six time the number is 6*x = 6x

Step 2:

product of the number and -3 is -3x

Step 3:

now let us make equation for it:

6x = -3x +45

adding 3x on the left side,

6x+3x = 45

9x = 45

dividing right side by 9

x=45/9 = 5

So the number is x=5



6 0
3 years ago
(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many
Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For  3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0
3 years ago
Uhhhhhmmmmmmmmmmmm wuts dis
vichka [17]

Answer:

Hey!

Step-by-step explanation:

Your answer would be 1/8

Have a nice day!♥

And ty XD

8 0
3 years ago
MULTIPLE CHOICE PLEASE HELP UWU
vodka [1.7K]

B)40 because (4)*50/5 is (4)*10

7 0
3 years ago
The equation
balandron [24]

Answer:

377282929191991929292

6 0
2 years ago
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