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3 years ago

Enter the value of p so the expression 5/6 - 1/3n is equivalent to p(5-2n).

1 answer:

8 0

Let's solve for p when the two expressions are equal.

$p(5-2n)=\frac{5}6 - \frac{1}3n \\\\ p=\frac{\frac{5}6-\frac{1}3n}{5-2n}*\frac{6}6= \frac{5-2n}{6(5-2n)} = \boxed{\frac{1}6}$

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The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 71.5 m

Zinaida [17]

Answer:

$G = 0.007523$

The number of cars the highway patrol officer would watch before a car that is seen is $E(X) = 1.6027$

The standard deviation is $s = 0.9829$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 71.5 \ miles/hour$

The standard deviation is $\sigma = 4.75 \ miles/hour$

The speed limit is $x = 70 \ miles /hour$

Generally the probability of getting a car that is moving with speed greater than the speed limit is mathematically represented as

$p =P(X > x ) = P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > -0.31579 )$

Here

$\frac{X - \mu }{\sigma } = Z(The \ standardized \ value \ of X )$

=> $p= P(X > 70) = P(Z > -0.31579 )$

From the z-table

$p = P(Z > -0.31579 ) = 0.62392$

$p = P(X > 70) = 0.62392$

Generally the probability of getting a car that is not moving with speed greater than the speed limit is mathematically represented as

$q = 1 - p$

=> $q = 1 - 0.62392$

=> $q = 0.37608$

Generally the probability of getting 5 cars that are not speeding is mathematically represented as

$G = q^5$

=> $G = (0.37608)^5$

=> $G = 0.007523$

Generally the number of cars that the highway patrol officer is expected to watch until the first car that is speeding is gotten is mathematically represented as

$E(X) = \frac{1}{p}$

=> $E(X) = \frac{1}{0.62392}$

=> $E(X) = 1.6027$

Generally the standard deviation is mathematically represented as

$s = \sqrt{\frac{1 - p }{ p^2} }$

=> $s = \sqrt{\frac{1 -0.62392 }{ (0.62392)^2} }$

=> $s = 0.9829$

8 0

3 years ago

Round the following numbers to the tenths place. 1. 1295.9549

yKpoI14uk [10]

1,296.0 I think this is right, I apologize if it’s wrong.

6 0

3 years ago

Helwp please thank uuu!

Minchanka [31]

Step-by-step explanation:

<h3>Given,</h3>

GRAM is a parallelogram
m<GMA = 66°
m<GRP = 32°
m<PAM = 41°

<h3>Solutions:</h3>

i) Since,

Angles on the same side of a transversal in a parallelogram, there sum is 180° so,

<RGM + <GMA = 180°

=> <RGM = 180° - <GMA

=> <RGM = 180° - 66°

=> <RGM = 114° (Ans)

ii) Since,

Opposite angles of a diagonal as a transversal (here RM) are equal so,

<GRP = <PMA = 32°

As we have <GMA = 66° so,

=> <GMP = <GMA - <PMA

= 66° - 32°

=> <GMP = 34° (Ans)

iii) Since,

Opposite angles of a parallelogram are equal so,

<RGM = <RAM = 114°

As we have <PAM = 41° so,

=> <GAR = <RAM - <PAM

= 114° - 41°

=> <GAR = 73° (Ans)

iv) Since,

We got <PMA = 32° and <PAM = 41°, so by angle sum property of a triangle PMA,

=> <MPA = 180° - 32° - 41°

=> <MPA = 107° (Ans)

7 0

2 years ago

Can 9, 6, and 5 be the lengths of the sides of a triangle? (yes or no answer)

iren [92.7K]

The answer is choice “Yes”

3 0

3 years ago

You started the trail with 500lbs. of food. You now have 282lbs. of food. What percentage of your starting amount do you have le

mestny [16]

Answer:

43.6%

Step-by-step explanation:

500-282=218

218/500=0.436

0.436=43.6%

3 0

3 years ago