First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
Answer:
13
Step-by-step explanation:
5-(-8)=13
To find the answer of this problem, we need to distibute and multiply all of the numbers with each other.
2x * x + 2x * 1 + 9 * x + 9 * 1
= 2x^2 + 2x + 9x + 9
= 2x^2 + 11x + 9
The answer would be the first option.
Hope this helps!
Answer:
f(x) = 1/2(4 - x)(x - 1)(x - 2)
Step-by-step explanation:
Considering zero's and a coefficient, the function is:
f(x) = a(x - 4)(x - 1)(x - 2)
Considering y-intercept:
f(0) = a(0 - 4)(0 - 1)(0 - 2)
4 = a(-4)(-1)(-2)
4 = -8a
a = -1/2
So the function is:
f(x) = -1/2(x - 4)(x - 1)(x - 2) = 1/2(4 - x)(x - 1)(x - 2)
Parallel lines have the same slope. So if a line has a slope of 2, a line parallel to it also has a slope of 2.
, we have
