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s344n2d4d5 [400]
3 years ago
8

I need help with this part, someone help me out :)

Mathematics
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

A & B

Step-by-step explanation:

A) V = pi×r²×h

= 3.142 × 8² × 5 = 1005.44 cm³

B) V = ⅓ × 18×16 × 12 = 1152 cm³

C) V = ½×5×3 × 7 = 52.5 cm³

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klasskru [66]
The equation is 30x + 25
 since the x is with the 30, that would be the cost per lesson, because you would multiply 30 by the number of lessons(x)

7 0
3 years ago
Joey has 30 model airplanes to paint. He has painted 18 models so far.
mixas84 [53]

Answer:

The answer is D, 60%.

Step-by-step explanation: How I did it is 100/30 then times that answer by 18.

8 0
2 years ago
Read 2 more answers
Pythagorean theorem question:)
AURORKA [14]
11^2 + 9^2 = x^2
121 + 81 = x^2
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4 0
3 years ago
The equation(function):10.00+.75x
valentinak56 [21]

Answer:

Answer:

b. -75x+57=-75x+57

Step-by-step explanation:

If an equation after solving does not give the solution but give a true statement then the equation has infinitely many solution,

In option a.

57x+57=-75x-75

57x + 75x = -75 - 57

132x = -132

⇒ x = -1

i.e. it has only one solution,

In option b.

-75x+57=-75x+57

-75x + 75x = 57 - 57

0 = 0  ( True )

i.e. it has infinitely many solution.

In option c.

75x+57=-75x+57

75x + 75x = 57 - 57

150x = 0

⇒ x = 0

i.e. it has only one solution,

In option d.

-57x+57=-75x+75

-57x + 75x = 75 - 57

18x = 18

⇒ x = 1

i.e. it has only one solution.

Step-by-step explanation:

6 0
3 years ago
2. Solve the<br> triangle.<br> a = 12, b = 22, C = 95°
djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4

Step-by-step explanation:

7 0
2 years ago
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