We can solve this problem using discriminant.
x^2-4x-12's discriminant is
(-4)^2-4*-12=16+48 which is clearly larger than 0
This means that it crosses over the axes 2 times.
In case you don't know what discriminant is, its in equation ax^2+bx+c
the discriminant is b^2-4ac.
If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.
Hope this helped at least a little bit :D
What is the question bruh not everybody know what you talkin bout
Answer:
(2,5)
Step-by-step explanation:
Answer:
Option C
Step-by-step explanation:
(7x^3y^3)^2
= (7)^2 * (x^3)^2 * (y^3)^2
= 49 * x^(3*2) * y^(3*2)
= 49x^6y^6
You have to distribute the terms in "7x^3 * y^3" each to the power of 2
(7)^2 * (x^3)^2 * (y^3)^2
Now you can apply the rule "(x^a)^b = x^a*b" and further simplify the expression
