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3 years ago

PLEASE HURRY I DONT HAVE MUCH TIME LEFT!

Mathematics

2 answers:

Tasya [4]3 years ago

7 0

Answer:

Step-by-step explanation:

NikAS [45]3 years ago

5 0

Answer:

Step-by-step explanation:

Because when you do the math and you solve the triangle you would get the answer

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Write the equation of a line whose graph has the same slope as

Sveta_85 [38]

Answer:

y= 1/3x -3

Step-by-step explanation:

For the y-int for 8x-2y=6 is (0, -3).

For the slope of 3x-9y=9 is 1/3.

3 0

3 years ago

Factor by grouping (sometimes called the ac-method).

lesya692 [45]

Answer:

Step-by-step explanation:

The arc method is basically finding what the a and c coefficients multiply to, and then finding the factors of that that add up to b.

Since we have the quadratic in the ax^2+bx+c form we don't have to adjust anything. Now, a = 8, b = 2 and c = -3. a*c = -24 so now we want to find all the factors of that.

-1 and 24

1 and -24

-2 and 12

2 and -12

-3 and 8

3 and -8

-4 and 6

4 and -6

And after that they repeat. It is important to note that you can use negative on either side, or if a*c was a positive number you could multiply two negatives like 24 can be and 12 as well as -1 and -12.

Now we want to look at all the factor pairs and find one that add together to equal 2 because b = 2. -4 + 6 does it, so there's our choice. Now we can rewrite the original quadratic as 8x^2-4x+6x-3. You can check that this is equivalent by combining like terms It's the same as rewriting it as 8x^2+2x-2-1 because -2 and -1 will combine to get -3. Anyway, now we can factor.

8x^2-4x+6x-3 You can imagine there being two sets of parenthesis.

( 8x^2-4x)+(+6x-3) Now from here we can factor something out of each parenthesis. e can factor out 4x fromt he first and 3 from the second.

4x(2x-1)+3(2x-3) Now, it may not be obvious but you can factor 2x-3 from each term. If that's not clear pretend 2x-3 = u

4xu + 3u Now hopefully it is clear you can factor out this u

u(4x+3) Then we know u = 2x-3 so

(2x-3)(4x+3) And it's factored.

I do want to mention you could have done this with 8x^2+6x-4x-3 with the +6 and -4 switched. I won't go through it here but it may help to do it yourself if you still don't quite understand. Let me know if there is something I can further explain though.

3 0

3 years ago

3m + 4m = 42 Please help. I think the answer is either 7 or -42

Katyanochek1 [597]

7m=42 thus m=6
Because 42/7=6

7 0

4 years ago

Read 2 more answers

0.01 is blank times as much as 0.001 please answer i will brainliest

coldgirl [10]

Answer:

100

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the three angles of the triangle with the given vertices: P(1,1,1), ????(1,−3,2), and ????(−3,2,5).

velikii [3]

Answer:

The three angles of the triangle are 90, 35.67 and 54.33 degrees.

Step-by-step explanation:

One way to find the angles of the triangle with vertices (1, 1, 1), (1, -3, 2), (-3, 2, 5) is using the definition of the dot product of two vectors, defined as:

a . b = |a| |b| cosФ [1]

Where |a| and |b| are the norms of vectors a and b, and cosФ is the cosine of the angle between either vector a and b.

If a = [ $\\ a_{1}, a_{2}, a_{3}$ ] and b = [ $\\ b_{1}, b_{2}, b_{3}$ ], then the dot product is simply a number (not a vector) obtained from:

a . b = $\\ a_{1}*b_{1} + a_{2}*b_{2} + a_{3}*b_{3}$

The norm of a vector (its length) is, for instance, |a| = $\\ \sqrt{{a_{1}^2 + {a_{2}}^2 + {a_{3}}^2}$ , for a vector in $\\ R^{3}$ .

Having all that into account, we can determine the angles of the triangle for each vertex using equation [1] and solving it for Ф.

<h3>Angle of the triangle for vertex in (1, 1, 1)</h3>

The vectors which form an angle from this vertex are the result of subtracting the vertex (1, 1, 1) to any of the remaining points (1, -3, 2) and (-3, 2, 5):

v(1, 1, 1) - v(1, -3, 2) = $\\ (1 - 1, 1 - (-3), 1 - 2) = (0, 1 + 3, -1) = (0, 4, -1)$

v(1, 1, 1) - v(-3, 2, 5) = $\\ (1 - (-3), 1 - 2, 1 - 5) = (1 + 3, -1, -4) = (4, -1, -4)$

The dot product for these vectors is:

[0, 4, -1] . [4, -1, -4] = [0 * 4 + 4 * -1 + -1 * -4] = 0 - 4 + 4 = 0

The norm for each vector is:

|(0, 4, -1)| = $\\ \sqrt{0^2 + 4^2 + -1^2} = \sqrt{0 + 16 + 1} = \sqrt{17}$

|(4, -1, -4)| = $\\ \sqrt{4^2 + -1^2 + -4^2} = \sqrt{16 + 1 + 16} = \sqrt{33}$

a . b = |a| |b| cosФ

$\\ 0 = \sqrt{17} * \sqrt{33} * cos{\theta}$

$\\ \frac{0}{\sqrt{17} * \sqrt{33}} = cos{\theta}$

$\\ cos^{-1}{0}} = cos^{-1}(cos{\theta})$

$\\ 90 = \theta$

In vertex (1, 1, 1) the angle of the triangle is 90 degrees. We have here a right triangle.

We have to follow the same procedure for finding the vectors for angles in vertices (1, -3, 2) and (-3, 2, 5), or better, after finding one of the previous angles, we find the remaining angle subtracting the sum of two angles from 180 degrees to finally obtaining the three angles in question.

Therefore, the other angles are 35.67 degrees and 180 - (90 + 35.67) = 180 - 125.67 = 54.33 degrees.

5 0

3 years ago