Step-by-step explanation:
radius of large sphere is R,
then volume is (4/3)*pie*R³
and
the radius of small sphere is r,
then volume is (4/3)*pie*r³
condition is,
volume of larger sphere is twice of the volume of smaller sphere.
then, (4/3)*pie*R³=2*(4/3)*pie*r³;
R³= 2r³
R=(2^⅓)*r
Answer:
n - 13
Step-by-step explanation:
n-4-9
We can combine like terms.
n - (4+9)
n - 13
There is approximately 1 solution for this equation
If Marie does not have soccer practice, then it is not a Tuesday
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].