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3 years ago

PLEASE HURRY I DONT HAVE MUCH TIME LEFT!

Mathematics

2 answers:

Tasya [4]3 years ago

7 0

Answer:

Step-by-step explanation:

NikAS [45]3 years ago

5 0

Answer:

Step-by-step explanation:

Because when you do the math and you solve the triangle you would get the answer

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WHICH TABLE IS A FUNCTION?<br> TABLE A<br> TABLE B<br> NEITHER<br> BOTH

Alexandra [31]

I believe it neither

3 0

3 years ago

Read 2 more answers

29/12 + 23/6 + 11/3 - 5 / 12

Hoochie [10]

Answer:

57/6 or 9 1/2.

Step-by-step explanation:

The lowest common denominator is 12 so we convert the fractions to denominator 12:

29/12 + 23/6 + 11/3 - 5 / 12

= 29/12 + 46/12 + 44/12 - 5/12

= 114/12

= 57/6

or 9 1/2

5 0

3 years ago

Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that

Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is $P(x_1 + x_2 \ge 2 )= 0.5940$

Step-by-step explanation:

From the question we are told that

The rate at which fire breaks out every 10 years is $\lambda = 1$

Generally the probability distribution function for Poisson distribution is mathematically represented as

$P(x) = \frac{\lambda^x}{ k! } * e^{-\lambda}$

Here x represent the number of state which is 2 i.e $x_1 \ \ and \ \ x_2$

Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

$P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 + x_2 \le 1 )$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [ P(x_1 = 0 , x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)$

=> $P(x_1 + x_2 \ge 2 ) = 1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}$

=> $P(x_1 + x_2 \ge 2 )= 1- [[0.3678 * 0.3679] + [0.3678 * 0.3679] + [0.3678 * 0.3679] ]$

$P(x_1 + x_2 \ge 2 )= 0.5940$

3 0

3 years ago

Simplify the expression. –42 ÷ (–6)

Vitek1552 [10]

The answer is 7
hope this helps!

4 0

3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

Shalnov [3]

Using translation concepts, the correct statement is given by:

If function f was translated down 4 units, the f(x) values would be subtracted by 4. A point in the table for the transformed function would be (1,9).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

A translation down 4 units means that the output values are subtracted by 4, hence the table would be given by:

x 1 2 3 4 5

f(x) 9 15 33 87 249

More can be learned about translation concepts at brainly.com/question/27948675

#SPJ1

3 0

2 years ago