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wolverine [178]
3 years ago
9

What is 0.0049 as a fraction

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0
It is 49/10000 because 49 is in the ten thousandth  column
docker41 [41]3 years ago
4 0
49/10,000 I think, not quite sure
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Enter the correct unit of measurement to complete the conversion. 100 liters = 1 what?
Elanso [62]
<span>10 milliliters (ml) =1 centiliter (cl)1 milliliter =1 cubic centimeter1 liter =1000 cubic centimeters100 centiliter =1 liter (L) = 1,000 milliliters<span>1000 liters =<span>1 kiloliter (km)
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             cubic decimeter<span> ?</span>

4 0
3 years ago
Given a data set consisting of 33 unique whole number observations, its five-number summary is:
Lemur [1.5K]

Answer:

given a data set of 33 unique whole number observation,its five number sumary is [16, 29, 40 ,54, 67]

Step-by-step explanation:

The p-th percentile in an ordered (from low to high) data set is a value such that p% of the data is less than that value. The quartiles of a data set are the 25th, 50th and 75th percentiles. (The 25th percentile is usually called the first quartile, the 50th percentile is usually called the median, and the 75th percentile is usually called the third quartile.)

The formula for finding the location (or position) of the (approximate) pth percentile in an ordered (from low to high) data set is  

L p=(n+1).p/100

For example, in the data set  [2,4,6,8,10,12,14,16,18]

the (approximate) 60th percentile is located at position  

L 60=(9+1).60/100=6

that is, the sixth data point (the value 12) is at the (approximate) 60th percentile.(Actually, only 55.6% of the data is below a 12.)

3 0
3 years ago
Solve the system by graphing:
AleksandrR [38]

Answer:

Step-by-step explanation:

its c

5 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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