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wolverine [178]
4 years ago
9

What is 0.0049 as a fraction

Mathematics
2 answers:
kipiarov [429]4 years ago
8 0
It is 49/10000 because 49 is in the ten thousandth  column
docker41 [41]4 years ago
4 0
49/10,000 I think, not quite sure
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Me. Webster is buying carpet for an exercise room in his basement. The room will have an area of 230 square feet. The width of t
Greeley [361]
230 divided by 12 1/2 is 18.4. 18.4 times the width is 230. so the length is 18.4.
8 0
4 years ago
20 points . I need help with this.
pishuonlain [190]

Answer:

1) 117

2) 51

3) congruent

4) to each other

Step-by-step explanation:

5 0
3 years ago
2,4 help me idk how to do it ASAP and show work if possible
azamat

Answer:155in^2

Step-by-step explanation:

Area of the poster board that she has left=Area of ||gm- area of ∆

Area of the poster board that she has left= 10*20-1/2*9*10

Area of the poster board that she has left=200-45=155in^2

7 0
3 years ago
What was your speed if you drove 325 miles in 5 1/4 hours?
Alexus [3.1K]

Answer:

62 miles per hour speed if you drove 325 miles in 5 1/4 hours

Step-by-step explanation:

Using formula:

\text{Speed} = \frac{\text{Distance}}{\text{Time}}

As per the statement:

if you drove 325 miles in 5 1/4 hours

⇒\text{Distance}=325 miles

and

Time = 5\frac{1}{4} = \frac{21}{4} = 5.25 hours

Then by above formula we have;

\text{Speed} = \frac{325}{5.25}=61.90 miles per hour

Therefore, 61.90 ≈ 62 miles per hour speed if you drove 325 miles in 5 1/4 hours

4 0
3 years ago
Read 2 more answers
The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu
zavuch27 [327]

Answer:

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

Explanation:

Given the equation of circle;

x^2+y^2-2x+6y-6=0

we want to re-write it in the form;

(x-h)^2+(y-k)^2=r^2

where;

\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}

Applying Completing the square method;

\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}

comparing the derived equation to the general form we have;

\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}

Therefore;

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

6 0
1 year ago
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