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3 years ago

Water that is heated move PLS HELP !!!

Chemistry

2 answers:

makkiz [27]3 years ago

5 0

Answer:

it moves faster when heated

Mila [183]3 years ago

5 0

Answer:

the answer is faster

Explanation:

why because water moves faster when heated

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Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves

hjlf

This is an incomplete question, here is a complete question.

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide:

$2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)$

In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide:

$3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)$

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answer : The net chemical equation for the production of manganese is:

$6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

Explanation :

The given two chemical reactions are:

(1) $2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)$

(2) $3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)$

First we are multiplying reaction 1 by 3, and reaction 2 by 2, we get:

(1)

(2) $6MnO_2(s)+8Al(s)\rightarrow 6Mn(s)+4Al_2O_3(s)$

Now we are adding both the reactions, we get the overall chemical reaction.

$6MnCO_3(s)+3O_2(g)+6MnO_2(s)+8Al(s)\rightarrow 6MnO_2(s)+6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

The $MnO_2$ is common on both side, by cancelling it, we get:

The net chemical equation for the production of manganese is:

$6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

5 0

4 years ago

Aluminum:

Scorpion4ik [409]

Whiteish silver
shiny
ductile
conductor
metal
left

3 0

3 years ago

Calculate the PH of a solution 0.030 MH2SO4

Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

4 0

3 years ago

If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a

max2010maxim [7]

Tetraedral shape. Like CH4.

3 0

3 years ago

Pure nitrogen (N2) and pure hydrogen (H2) are fed to a mixer. The product stream has 40.0% mole nitrogen and the balance hydroge

LuckyWell [14K]

Explanation:

The given data is as follows.

Mass flow rate of mixture = 1368 kg/hr

$N_{2}$ in feed = 40 mole%

This means that $H_{2}$ in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas $(N_{2} + H_{2})$ in feed stream.

Hence, calculate the total mass flow rate as follows.

40 moles/hr of N_{2}/hr (28 g/mol of $N_{2}$ ) + 60 moles/hr of $H_{2}/hr$ (2 g/mol of $H_{2}$ )

$40 \times 28 g/hr + 60 \times 2 g/hr$

= 1120 g/hr + 120 g/hr

= 1240 g/hr

= $\frac{1240}{1000}$ (as 1 kg = 1000 g)

= 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

$\frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr$

= 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of $N_{2}$ into the reactor as follows.

$0.4 \times 110322.58 moles/hr$

= 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of $N_{2}$ into the reactor as follows.

$0.028 kg \times 44129.03 mol/hr$

= 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

3 0

3 years ago