Question

At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?

Answer 1

Answer:

447,25k

Explanation:

According to the ideal gas law

$PV=nRT$

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

$T=\frac{PV}{nR}\\ \\T=\frac{12,3L.1,95atm}{0,654mol.0,082(L.atm/K.mol)}\\ \\T=447,25K$