8/9 + 4/7=1 29/63 ESTIMATE:2
8/9 - 4/7=<span>20/63 ESTIMATE:0
</span>
Answer:
0.002
Step-by-step explanation:
We need to estimate the standard error of the mean, so we can use it as a standard deviation of the sample of 50 males.
Standard error of the mean = standard deviation/√n
Standard error of the mean = 32/√50 = 4.52
Now we can use this Standard error of the mean to estimate z as follows:
Z = (x – mean)/standard deviation
Z = (190-177)/4.52
Z = 2.87
Using a Z table we can find probability that mean is under 190
P (z<190)= 0.998
For the probability that the mean exceed 190 lbs we substract from 1
P(z>190) = 1 - 0.998 = 0.002
A basketball is the shape of a sphere.
The volume of a sphere is given by
![V= \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3)
Given that the diameter of the basketball is 10 in., thus the radius is 10 / 2 = 5 in.
Thus, the volume of the basketball is given by
![V= \frac{4}{3} \pi(5)^3 \\ \\ = \frac{4\times125}{3} \pi=523.6\ in^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%285%29%5E3%20%5C%5C%20%20%5C%5C%20%3D%20%5Cfrac%7B4%5Ctimes125%7D%7B3%7D%20%5Cpi%3D523.6%5C%20in%5E3)
Therefore, The best approximate of the volume of the basketball is
Given:
![\frac{1}{3}v=-5](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dv%3D-5)
To get rid of the fraction, we can multiply both sides by the denominator, which is 3. This will cancel the fraction:
![3(\frac{1}{3}v)=3(-5)](https://tex.z-dn.net/?f=3%28%5Cfrac%7B1%7D%7B3%7Dv%29%3D3%28-5%29)
We are left with:
![v=-15](https://tex.z-dn.net/?f=v%3D-15)