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LuckyWell [14K]
3 years ago
15

A scientist is investigating the effects of salinity on fish development in the Atlantic Ocean. He places fertilized fish eggs i

n an aquarium that contains lower salinity than typical Atlantic Ocean water. He observes that the fertilized eggs fail to develop. He concludes that fish eggs do not develop in conditions with low salinity. Why is this an invalid conclusion? The experiment lacks an experimental group. The experiment does not measure any dependent variables. The experiment does not have a group tested in normal salinity. The experiment changes more than one variable at once. i need help ASAP PLEASE
Mathematics
1 answer:
forsale [732]3 years ago
4 0

The experiment does not have a group tested in mornal salinity <––– the answer

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Answer:

b) 0.2961

c) 0.2251

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We are given the following information:

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a) Conditions for binomial probability distribution

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P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961

c) P( exactly 3 trucks fail the inspection)

p = 0.25

P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251

d) Mean and standard deviation

\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667

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