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Xelga [282]
3 years ago
14

Two young sumo wrestlers decided to go on a special diet to gain weight rapidly. They each gained weight at a constant rate. The

weight (in kilograms) of the first wrestler as a function of time (in months) is given by the following table of values: \text{Time}Timestart text, T, i, m, e, end text (months) \text{Weight}Weightstart text, W, e, i, g, h, t, end text (kilograms) 333 959595 4.54.54, point, 5 101.75101.75101, point, 75 666 108.5108.5108, point, 5 The graph of the weight (in kilograms) of the second wrestler as a function of time (in months) is shown below. Which wrestler weighed more at the beginning of the diet? Choose 1 answer: Choose 1 answer: (Choice A) A The first wrestler (Choice B) B The second wrestler (Choice C) C They weighed the same Which wrestler gained weight faster? Choose 1 answer: Choose 1 answer: (Choice A) A The first wrestler (Choice B) B The second wrestler (Choice C) C They both gained weight at the same rate
Mathematics
1 answer:
Radda [10]3 years ago
5 0

Answer: the first wrestler gains more at the beginning, the second wrestler gains more faster

Step-by-step explanation:

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Answer:

Length=10.5\ ft

Width=10.5\ ft

Area=110.25\ ft^{2}

Step-by-step explanation:

Let

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y---> the width of the rectangular garden

we know that

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P=42\ ft

so

42=2(x+y)

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Remember that the area of rectangle is equal to

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A=21x-x^{2}----> this is a vertical parabola open downward

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see the attached figure

so

x=10.5\ ft

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