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3 years ago

Drawn two arrays that represent 12

Mathematics

1 answer:

kupik [55]3 years ago

3 0

●●●●
●●●● That is 4×3=12
●●●● 4 across 3 down

●●●●●● That's 6×2=12
●●●●●● 6 across 2 down

Hope this helped☺

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Lana draws a triangle( LMN) on the coordinate plane. What is the perimeter of the triangle( LMN)? Round to the nearest unit.

lys-0071 [83]

Answer:

The answer is "25".

Step-by-step explanation:

Please find the graph in the attachment.

$Longest \ side= 12$

Calculating the triangle two other sides:

$=\sqrt{3^2+6^2}\\\\=(9+36)\\\\=45$

let

$\to \sqrt{45}= 6.7.\\\\\to 6.7\times 2=13.4\\\\\to 13.4+12=25.4 \approx 25$

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2 years ago

The graphs of the two lines 4x=3y+23 and 4y+3x=-19

dem82 [27]

Answer: D. Are perpendicular

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3 years ago

You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t

icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

$P(H)=\frac{13}{52}=0.25$

Compute the probability of selecting a Spade second as follows:

$P(S)=\frac{13}{51}=0.255$

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

$P(1st\ H\cap 2nd\ S)=P(H)\times P(S)$

$=0.25\times 0.255\\=0.06375\\\approx 0.064$

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

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3 years ago

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Scorpion4ik [409]

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Hope this helps :)

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