Answer:
A. The red cylinder
Step-by-step explanation:
<h2><u>Which cylinder has the greater volume </u></h2><h3><u>volume of a cylinder</u></h3>
formula:
V = ![\pi r^{2} h](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D%20h)
<h3><u>volume of the blue cylinder</u></h3>
V = ![\pi r^{2} h](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D%20h)
= ![\pi * 1^{2} * 6](https://tex.z-dn.net/?f=%5Cpi%20%2A%201%5E%7B2%7D%20%2A%206)
=18.84956
to 2 dp
volume of the blue cylinder is <u>18.85 </u>
<h3><u>volume of the red cylinder</u></h3>
V = ![\pi r^{2} h](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D%20h)
= ![\pi * 2^{2} * 3](https://tex.z-dn.net/?f=%5Cpi%20%2A%202%5E%7B2%7D%20%2A%203)
= 37.69911
to 2dp
volume of the red cylinder is 37.70
<h3><u>the cylinder which has the greater volume is : A. The red cylinder</u></h3>
3x + 6(2x - 5) = 3x - 3
First, take out '3x' on both sides.
Second, divide both side by '6'.
Third, find the GCF of 3 and 6.
The GCF is 3.
Fourth, divide the numerator by the GCF.
![3](https://tex.z-dn.net/?f=3)
÷
Fifth, divide the denominator by the GCF.
![6](https://tex.z-dn.net/?f=6)
÷
Sixth, rewrite the fraction in simplest form.
Seventh, add '5' to both sides.
Eighth, make the denominators the same.
Ninth, simplify so that the denominators are the same.
Tenth, combine the denominators.
Eleventh, subtract '-1 + 10' to get '9'.
Twelfth, divide both sides by '2'.
Thirteenth, multiply '2 × 2' to get '4'.
![x = \frac{9}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B9%7D%7B4%7D%20)
Answer as fraction:
![x = \frac{9}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B9%7D%7B4%7D%20)
Answer as decimal:
X is always going to go first so it goes like this (x,y) so it would be (2,5) hope this helps u some
I don't know how to do the stuff in bold, but he made 28 out of 35 shots
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