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kirill115 [55]
3 years ago
11

P(x)=x^3−4x^2+cx+2 (x-2) find c

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

I already answered a question but it didn’t count I guess

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2 1/3 divided by 1/4
zloy xaker [14]
Answer:

28/3

Step-by-step explanation:

2 1/3 divided by 1/4

We’ll start by 2 1/3

Multiply 3 x 2 and then add 1

3 x 2 = 6 + 1 = 7

Then add the denominator back

7/3

Now divide 7/3 by 1/4 like this!

Start by multiplying 4 by 7

4 x 7 = 28

Then multiply 3 by 1

3 x 1 = 3

Final results: 28/3
7 0
3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
What is the y-intercept of the function y= -1/2cos(3/2x)
Flauer [41]

Answer: (0,-1/2)

Step-by-step explanation:

Edge :-)

5 0
3 years ago
What is the answer ​
Mandarinka [93]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
If the Leaning Tower of Pisa (which is roughly cylindrical) has a height of 55 meters, radius of 8 meters, what is the volume?
valentinak56 [21]

Answer:

Option C. V=3,520\pi\ m^3

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=8\ m

h=55/ m

substitute

V=\pi (8)^{2} (55)

V=3,520\pi\ m^3

8 0
3 years ago
Read 2 more answers
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