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wel
2 years ago
8

Graph and label each figure in its image under the given counterclockwise rotation about the origin. Give the new coordinates. p

ls help ASAP!!!
Mathematics
1 answer:
Iteru [2.4K]2 years ago
6 0

Answer:

Cscscscbsc s

Step-by-step explanation:

Csucbhscucbhsbhczj

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How to I find a? It’s round to the nearest tenth.
Irina18 [472]

Answer:

a ≈ 21.8

Step-by-step explanation:

We require the third angle in the triangle

Subtract the sum of the 2 angles from 180

third angle = 180° - (75 + 31.8)° = 180° - 106.8° = 73.2°

Using the Sine rule, that is

\frac{a}{sin73.2} = \frac{22}{sin75} ( cross- multiply )

a × sin75° = 22 × sin73.2° ( divide both sides by sin75° )

a = \frac{22sin73.2}{sin75} ≈ 21.8 ( to the nearest tenth )

7 0
3 years ago
You have been asked to find the inverse of f (x) = 3+Vx - 1. What would your
Paha777 [63]

Answer:

Add 1 to both sides of the equation.

Subtract 3 from both sides of the equation.

Step-by-step explanation:

The inverse of a function refers to that function that tends to undo another function.

If we intend to find the inverse of the function, f(x) = 3+ V2 - 1, we have to first add 1 to both sides of the equation and subsequently subtract 3 from both sides of the equation before taking the square root of both sides to obtain the inverse function.

Step-by-step explanation:

I hope this helps you :)

<em><u>-KeairaDickson</u></em>

8 0
3 years ago
Factor. x^2-5x-84 pls help
vagabundo [1.1K]

Answer:

(x-12) (x+7)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(with steps please) Find the inverse Laplace transform, f(t), of the function: 16/(s-4)^3
Stells [14]

Answer:  The required inverse transform of the given function is

f(t)=8t^2e^{4t}.

Step-by-step explanation:  We are given to find the inverse Laplace transform, f(t), of the following function :

F(s)=\dfrac{16}{(s-4)^3}.

We have the following Laplace formula :

L\{t^ne^{at}\}=\dfrac{n!}{(s-a)^{n+1}}\\\\\\\Rightarrow L^{-1}\{\dfrac{1}{(s-a)^{n+1}}\}=\dfrac{t^ne^{at}}{n!}.

Therefore, we get

f(t)\\\\=L^{-1}\{\dfrac{16}{(s-4)^3}\}\\\\\\=16\times\dfrac{t^{3-1e^{4t}}}{(3-1)!}\\\\\\=\dfrac{16}{2}t^2e^{4t}\\\\\\=8t^2e^{4t}.

Thus, the required inverse transform of the given function is

f(t)=8t^2e^{4t}.

6 0
3 years ago
What is the metric equivalent in meters to 1250 feet?
Dvinal [7]

381 meters because you divide 1250 by 3.281 and you get 381 meters

6 0
3 years ago
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