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katovenus [111]
3 years ago
8

The graph of f(x)=4^x, stretches horizontally by a factor of 3

Mathematics
1 answer:
leonid [27]3 years ago
4 0

hope it helps you!!!!!!!!!

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Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked?
fredd [130]
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
3 0
3 years ago
The polygons are similar, but not necessarily drawn to scale. Find the value of x.
alexandr402 [8]

If the shapes are similar, the correspondent sides are in proportion:

AB\div DE = BC \div EF

Let's plug the values and solve for x:

5x \div 5 = 4 \div x \iff \dfrac{5x}{5}=\dfrac{4}{x}\iff x = \dfrac{4}{x}

Multiply both sides by x to get

x^2=4 \iff x=\pm2

The only feasible solution, though, is x=2, because it wouldn't make sense to have negative lengths.

5 0
3 years ago
The amount of Interest a store charges a customer for buying on the installment plan is a?
nasty-shy [4]

annual percentage rate

7 0
3 years ago
Two different types of injection-molding machines are used toform plastic parts. A part is considered defective if it hasexcessi
erma4kov [3.2K]

Answer:

a) In hypothesis testing the null hypothesis is never accepted. It is rejected or not rejected. In this case, couldn't be rejected, so it is possible that both machines produce the same fraction of defective parts. It is reasonable to conclude that both machines produce the same fraction of defective parts, although this test doesn't conclude this.

b) P-value =  0.143

c) -0.008\leq \pi_1-\pi_2\leq 0.054

Step-by-step explanation:

<em>In this problem we have to do a Test of Differences between Proportions</em>

<em />

The first step is to state the null and alternative hypothesis

H_0: \pi_1-\pi_2=0\\\\H_1:  \pi_1-\pi_2\neq 0

The null hypothesis represents the case where both machines are expected to produce the same amount of defective parts.

The second step is determine the significance level. In this case is α=0.05.

The third step is to calculate the difference in the proportions

p_1-p_2=(15/300)-(8/300)=0.050-0.027=0.023

The fourth step is to estimate the standard deviation of the difference between proportions.

s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}

As n_1=n_2, we can calculate p as p=(p_1+p_2)/2=(0.050+0.027)/2=0.0385.

Then:

s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}\\\\s_{p_1-p_2}=\sqrt{\frac{2*0.0385(1-0.0385)}{300}}=0.0157

The fifth step is to compute p, the probability (or probability value).

z=(p_1-p_2)/s_{p_1-p_2}=0.023/0.0157= 1.465

A z table can be used to find that the two-tailed probability value for a z=1.465 is P(x>|z|)=0.143.

The probability value (P-value) is 0.143. As it is bigger than the significance level (0.05),  the effect is not significant. We can not reject the hypothesis.

To construct a 95% CI we can write:

(p_1-p_2)-z*s_{p_1-p_2}\leq \pi_1-\pi_2\leq (p_1-p_2)+z*s_{p_1-p_2}

For a 95% CI, z=1.96. The estimated standard deviation is the same calcaulated before. Now we can calculate:

(p_1-p_2)-z*s_{p_1-p_2}\leq \pi_1-\pi_2\leq (p_1-p_2)+z*s_{p_1-p_2}\\\\(0.050-0.027)-1.96*0.0157\leq \pi_1-\pi_2\leq (0.050-0.027)+1.96*0.0157\\\\0.023-0.031\leq \pi_1-\pi_2\leq 0.023+0.031\\\\ -0.008\leq \pi_1-\pi_2\leq 0.054

5 0
3 years ago
Use 3.14 for π<br><br> Please consider helping!<br> Any help is appreciated!
Vikentia [17]

The circumference of the circle is 53.41.

8 0
3 years ago
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