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3 years ago

What is the center and radius of the circle with the given equation (x-1)^2+(y+1)^2=4?

2 answers:

8 0

Hi there! The centre of this circle is (1, -1) and the radius is 2.

The standard form of a circle's formula is
$(x - a) {}^{2} + ( {y - b)}^{2} = r {}^{2}$

With a and b representing the coordinates of the centre and r representing the radius of the circle. Since in this situation r^2 equals 4, the radius (r) has to be 2.

Mrrafil [7]3 years ago

4 0

The center is x = 1, y = -1.
The radius is 2.

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Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y <

levacccp [35]

Solution-

The given inequalities are,

$y < 2x-7,\\\\y\geq-\frac{1}{2}x+3$

Part A

As the former inequality is only '<' so it will be represented as dotted line, but in case of the later inequality there is '≥' so it will be represented as a solid line.

This happens because in only '<, >' the values must be either lesser or greater than y, they can't take the values of y, but in case of '≤, ≥' the values can be equal to y.

Taking origin (0, 0) and putting in the first inequality.

$\Rightarrow 0< 2(0)-7\\\\\Rightarrow 0\nless -7$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

Again taking origin (0, 0) and putting in the second inequality.

$\Rightarrow 0\geq-\frac{1}{2}0+3\\\\\Rightarrow 0\ngeqslant 3$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

The second attachment contains the feasible region.

Part B

In order to know whether the point (3, −7) is included in the solution area for the system or not, we must put it in both the equations, if it satisfies both then only it is within the solution area.

$\Rightarrow -7< 2(3)-7,\ -7\geq-\frac{1}{2}(3)+3\\\\\Rightarrow -7$

As the point (3, -7) only satisfies first inequality, but not the second inequality so this point won't be in the solution area.

6 0

3 years ago

Read 2 more answers

Factor x3 + x2 + x + 1 by grouping. What is the resulting expression?

Svet_ta [14]

X^3 +x^2 +x +1 = x^2(x +1) + x +1 = (x^2 +1)(x +1)

hope helped

8 0

3 years ago

Read 2 more answers

Find the mean of the following data set. 8, 5, 15, 12, 10 12.5 10 14 50

cluponka [151]

Answer:

Step-by-step explanation:

8+5+15+12+10= 50 / 5 = 10

7 0

3 years ago

List five numbers that hav 3,5,and 7 as prime factors

Yuki888 [10]

15 has prime factors of 5,3
21 has prime factors of 7,3
35 has prime factors of 7,5
105 has prime factors of 7,5,3
315 has prime factors of 7,5,3,3
hope this helps

7 0

4 years ago

M and n are both integers. Select all the statements that are true if m and n are also equal to each other.

telo118 [61]

The question is incomplete. The complete question is :

M and n are both integers. Select all the statements that are true if m and n are also equal to each other.

A. m - n = n - m

B. 0 = m - n

C. m + (-n) = m - n

D. m + n = 0

Answer :

A. m - n = n - m

B. 0 = m - n

C. m + (-n) = m - n

Explanation :

It is given that m and n are integers and they both are equal to each other.

i.e. m = n

Therefore for option (A),

m - n = n - m

m - m = m - m (since m and n are equal)

0 = 0

Therefore, the statement (A) is true.

For option (B),

0 = m - n

0 = m - m (since m and n are equal)

0 = 0

Therefore, the statement (B) is true.

For option (C),

m + (-n) = m - n

m + (-m) = m - m (since m and n are equal)

m - m = m - m

0 = 0

Therefore, the statement (C) is true.

Now for option (D),

m + n = 0

m + m ≠ 0 (since m and n are equal)

2m ≠ 0

Therefore, the statement (D) is false.

Hence, the options (A), (B) and (C) are true.

3 0

3 years ago